MCQ Questions for Class 12 Physics Chapter 3 Current Electricity Part-2 with Answers

Current Electricity Part-2 Class 12 Physics MCQs Questions with Answers

Check the below NCERT MCQ Questions for Class 12 Physics Chapter 3 Current Electricity Part-2 with Answers Pdf free download. MCQ Questions for Class 12 Physics with Answers were prepared based on the latest exam pattern. We have Provided Current Electricity Part-2 Class 12 Physics MCQs Questions with Answers to help students understand the concept very well.

Class 12 Physics Chapter 3 Quiz

Class 12 Physics Chapter 3 MCQ Online Test

You can refer to NCERT Solutions for Class 12 Physics Chapter 3 Current Electricity Part-2 to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

Current Electricity Part-2 Class 12 Physics MCQ online test

Q1.	A galvanometer acting as a volt meter will have with its coil.
	A.a high resistance in parallel
	B.a high resistance in series
	C.a low resistance in parallel
	D.a low resistance in series

Ans: a high resistance in series

Q2.	When three identical bulbs of 60 W, 200 V rating are connected in series to a 200 V supply, the power drawn by them will be:
	A.20 W
	B.60 W
	C.180 W
	D.10 W

Ans: 20 W

Q3.	n resistances, each of R Ω, are connected in parallel gives an equivalent resistance of R Ω. If these resistances were , connected in series, the combination would have a resistance in Ω is equal to
	A.n²R
	B.R/n²
	C.R/n
	D.nR

Ans: n²R

Q4.	Why is the Wheatstone bridge more accurate than other methods of measuring resistances: ‘
	A.It is a null method
	B.It is based on Kirchhoffs laws
	C.It has four resistances
	D.It does not involve ohm’s law

Ans: It is a null method

Q5.	A potential difference of 10 V is applied across a conductance of 2 S. The current in the conductor will be :
	A.20 A
	B.5 A
	C.0.2 A
	D.None of these

Ans: 20 A

Q6.	Ohm’s law is valid when the temperature of conductor is :
	A.very low
	B.very high
	C.varying
	D.constant

Ans: constant

Q7.	The emf of a car battery is about:
	A.2.5 V
	B.4.5 V
	C.8.6 V
	D.12 V

Ans: 12 V

Q8.	Emf is measured in :
	A.joule
	B.joule/coulomb
	C.joule-coulombs
	D.joule/coulomb/metre

Ans: joule/coulomb

Q9.	1 kilowatt hour is commonly known as :
	A.unit
	B.1 faraday
	C.1 curie
	D.None of these

Ans: unit

Q10.	How many joules are equal to I kWh ?
	A.3.6 × 10⁴
	B.3.6 × 10⁵
	C.3.6 × 10⁶
	D.None of these

Ans: 3.6 × 10⁶

Q11.	The temperature coefficient of resistance is expressed in :
	A.°C
	B.°C^-1
	C.m°C^-1
	D.None of these

Ans: °C^-1

Q12.	Copper wire is used as connecting wire because :
	A.copper has high electrical resistivity
	B.copper has low electrical resistivity
	C.copper has low electrical conductivity
	D.copper has high value of elasticity

Ans: copper has low electrical resistivity

Q13.	The heat sensitive device whose resistivity changes very rapidly with change of temperature is called a :
	A.resistor
	B.super-conductor
	C.thermocouple
	D.thermistor

Ans: thermistor

Q14.	The phenomenon of super-conductivity was discovered by :
	A.Ohm
	B.Onnes
	C.Edison
	D.None of these

Ans: Onnes

Q15.	The specific resistance of a conductor increases with :
	A.increase in temperature
	B.increase in cross-sectional area
	C.decrease in length
	D.decrease in cross-sectional area

Ans: increase in temperature

Q16.	In an experiment with potentiometer, null point with a cell is found at 240 cm. When the cell is shunted with a resistance 2 Ω, the null point becomes 120 cm internal resistance of cell is :
	A.4 Ω
	B.2 Ω
	C.1 Ω
	D.\(\frac{1}{2}\) Ω

Ans: 2Ω

Q17.	Two conductors of equal length and radii the ratio of 2 : 3 are; connected in parallel the source of electricity. The ratio of the velocity of electrons in the conductor be :
	A.2 : 3
	B.4 : 9
	C.1 : 1
	D.3 : 2

Ans: 1 : 1

Q18.	The charge flowing in a conductor varies with time as : q = αt \(\frac{1}{2}\) βt² + \(\frac{1}{6}\) γt³ Where α, β, γ are positive constants. Then the initial current (l) is given by the condition :
	A.l = α
	B.l = α²
	C.l = α^-1
	D.None of these

Ans: l = α

Q19.	In questions 38, the maximum value of current (l_max) is given by the condition :
	A.l_max = α – \(\frac{β^2}{2γ}\)
	B.l_max = α – \(\frac{β^2}{2α}\)
	C.l_max = α – \(\frac{γ^2}{2β}\)
	D.None of these

Ans: l_max = α – \(\frac{β^2}{2γ}\)

Q20.	In questions 38, the line (t) after which the value of current reaches a maximum values given by :
	A.t = \(\frac{α}{β}\)
	B.t = \(\frac{β}{α}\)
	C.t = \(\frac{β}{γ}\)
	D.t = \(\frac{γ}{β}\)