MCQ Questions | Class 10 Maths Chapter 1 | Real Numbers with Answers

MCQ | Real Numbers Class 10 | Sat D

Check the below NCERT MCQ Questions for Class 10 Maths Chapter 1 Real Numbers with Answers Pdf free download. MCQ Questions for Class 10 Maths with Answers were prepared based on the latest exam pattern. We have Provided Real Numbers Class 10 Maths MCQs Questions with Answers to help students understand the concept very well.

Objective Question | NCERT Maths Class 10

NCERT Solutions Class 10 Maths
Book:	National Council of Educational Research and Training (NCERT)
Board:	Central Board of Secondary Education (CBSE)
Class:	10th
Subject:	Maths
Chapter:	1
Chapters Name:	Real Numbers
Medium:	English

Ncert Solutions for Class 10 Maths | Objective Type Questions

You can refer to NCERT Solutions for Class 10 Maths Chapter 1 Real Numbers to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

Real Numbers | Class 10 Maths | NCERT Solutions

Q1.	If LCM (77, 99) = 693, then HCF (77, 99) is
	A. 11
	B. 7
	C. 9
	D. 22

Ans: 11

Q2.	Euclid’s division lemma states that for two positive integers a and b, there exist unique integer q and r such that a = bq + r, where r must satisfy
	A. a < r < b
	B. 0 < r ≤ b
	C. 1 < r < b
	D. 0 ≤ r < b

Ans: ≤ r < b

Q3.	For positive integers a and 3, there exist unique integers q and r such that a = 3q + r, where r must satisfy:
	A. 0 < r < 3
	B. 1 < r < 3
	C. 0 < r < 3
	D. 0 < r < 3

Ans: < r < 3

Q4.	Find the greatest number of 5 digits, that will give us remainder of 5 when divided by 8 and 9 respectively.
	A. 99921
	B. 99931
	C. 99941
	D. 99951

Ans: 99941
Explaination: The greatest number will be multiple of LCM (8, 9)
LCM of 8 and 9 = 72
On verification we find that 99941 when divided by 72 leaves remainder 5.

Q5.	For some integersp and 5, there exist unique integers q and r such that p – 5q + r. Possible values of r are
	A. 0 or 1
	B. 0, 1 or 2
	C. 0, 1, 2 or 3
	D. 0, 1, 2, 3 or 4

Ans: , 1, 2, 3 or 4
Explaination: According to Euclids division lemma, p – 5q + r, where 0 < r < 5
⇒ r = 0,1,2, 3, 4
So, possible values of r are 0, 1,2, 3 or 4.

Q6.	If two positive integers a and b are written as a = x’y1 and b = xyi, where x, y are prime numbers, then HCF(a, b) is Also, find LCM of (a, b).
	A. xy
	B. xy²
	C. x³y³
	D. x²y²

Ans: xy²
Explaination: Here, a = x³y² and b = xy³
⇒ a=x × x × x × y × y
and b = xy × y × y
∴ HCF(a, b) = x × y × y
= x × y² = xy²
LCM = x³y³

Q7.	If two positive integers p and q can be expressed as p = ab² and q = c³b; where a, b being prime numbers, then LCM (p, q) is equal to
	A. ab
	B. crb²
	C. a³b²
	D. c²b³

Ans: a³b²
Explaination:LCM (p, q) = a³b²

Q8.	Two alarm clocks ring their alarms at regular intervals of 50 seconds and 48 seconds. If they first beep together at 12 noon, at what time will they beep again for the first time ?
	A. 12.20 pm
	B. 12.12 pm
	C. 12.11pm
	D. none of these

Ans: none of these

Explaination:

LCM of 50 and 48 = 1200
∴ 1200 sec = 20 min
Hence at 12.20 pm they will beep again for the first time.

Q9.	If A = 2n + 13, B = n + 7, where n is a natural number, then HCF of A and B is:
	A. 2
	B. 1
	C. 3
	D. 4

Ans: 1

Explaination:

Taking different values of n we find
that A and B are coprime.
∴ HCF = 1

Q10.	There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. The total number of sections thus formed are:
	A. 22
	B. 16
	C. 36
	D. 21

Ans: 16

Explaination:

HCF of 576 and 448 = 64
∴ Number of sections = \(=\frac{576}{64}+\frac{448}{64}\)
= 9 + 7 = 16

Q11.	The HCF of 2472, 1284 and a third number N is 12. If their LCM is 23 x 32 x 5 x 103 x 107, then the number Nis :
	A. 22 x 32 x 7
	B. 22 x 33 x 103
	C. 22 x 32 x 5
	D. 24 x 32 x ll

Ans: 22 x 32 x 5

Explaination:

2472 = 2³ × 3 × 103
1284 = 2² × 3 × 107
∵ LCM = 2³ × 3² × 5 × 103 × 107
∴ N = 2² × 3² × 5 = 180

Q12.	Two natural numbers whose difference is 66 and the least common multiple is 360, are:
	A. 120 and 54
	B. 90 and 24
	C. 180 and 114
	D. 130 and 64

Ans: 9 and 24

Explaination:

Difference of 90 and 24 = 66
and LCM of 90 and 24 = 360
∴ Numbers are 90 and 24.

Q13.	HCF of 52 x 32 and 35 x 53 is:
	A. 53 x 35
	B. 5 x 33
	C. 53 x 32
	D. 52 x 32

Ans: 52 x 32

Explaination:

HCF of 5² × 3² and 3⁵ × 5³
= 5² × 3²

Q14.	4 Bells toll together at 9.00 am. They toll after 7, 8, 11 and 12 seconds respectively. How many times will they toll together again in the next 3 hours?
	A. 3
	B. 4
	C. 5
	D. 6

Ans: 5

Explaination:

LCM of 7, 8, 11, 12 = 1848
∴ Bells will toll together after every 1848 sec.
∴ In next 3 hrs, number of times the bells will toll together
\(=\frac{3 \times 3600}{1848}\) = 5.84
⇒ 5 times.

CBSE Solutions | Ncert Solutions Maths Class 10

NCERT Solutions | 10th Maths Guide

NCERT | Class 10 Maths Solution

Ncert Solutions for Class 10 Maths

MCQ Questions | Class 10 Maths Chapter 1

MCQ Questions | Class 10 Maths Chapter 1 | Real Numbers with Answers

MCQ | Real Numbers Class 10 | Sat D

Objective Question | NCERT Maths Class 10

Ncert Solutions for Class 10 Maths | Objective Type Questions

Real Numbers | Class 10 Maths | NCERT Solutions

CBSE Solutions | Ncert Solutions Maths Class 10

NCERT Solutions | 10th Maths Guide

NCERT | Class 10 Maths Solution

Ncert Solutions for Class 10 Maths

Ncert Solutions for Class 10 Maths Chapter 1

Ncert Solutions for Class 10 Maths Chapter 2

Ncert Solutions for Class 10 Maths Chapter 3

Ncert Solutions for Class 10 Maths Chapter 4

Ncert Solutions for Class 10 Maths Chapter 5

Ncert Solutions for Class 10 Maths Chapter 6

Ncert Solutions for Class 10 Maths Chapter 7

Ncert Solutions for Class 10 Maths Chapter 8

Ncert Solutions for Class 10 Maths Chapter 9

Ncert Solutions for Class 10 Maths Chapter 10

Ncert Solutions for Class 10 Maths Chapter 11

Ncert Solutions for Class 10 Maths Chapter 12

Ncert Solutions for Class 10 Maths Chapter 13

Ncert Solutions for Class 10 Maths Chapter 14

Ncert Solutions for Class 10 Maths Chapter 15

NCERT SOLUTIONS

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