MCQ Questions for Class 12 Chemistry Chapter 13 Amines Part-1 with Answers

Amines Part-1 Class 12 Chemistry MCQs Questions with Answers

Check the below NCERT MCQ Questions for Class 12 Chemistry Chapter 13 Amines Part-1 with Answers Pdf free download. MCQ Questions for Class 12 Chemistry with Answers were prepared based on the latest exam pattern. We have Provided Amines Part-1 Class 12 Chemistry MCQs Questions with Answers to help students understand the concept very well.

Class 12 Chemistry Chapter 13 Quiz

Class 12 Chemistry Chapter 13 MCQ Online Test

You can refer to NCERT Solutions for Class 12 Chemistry Chapter 13 Amines Part-1 to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

Amines Part-1 Class 12 Chemistry MCQ online test

Q1.	Nitrogen atom of amino group is ………. hybridised.
	A.sp
	B.sp²
	C.sp³
	D.sp³d

Ans: sp³

Q2.	Which of the following should be most volatile? I. CH₃CH₂CH₂NH₂ II. (CH₃)₃N IV. CH₃CH₂CH₃
	A.II
	B.IV
	C.I
	D.III

Ans: IV

Q3.	C₃H₈N cannot represent
	A.1° ammine
	B.2° ammine
	C.3° ammine
	D.quartemary ammonium salt

Ans: quartemary ammonium salt

Q4.	Identify the correct IUPAC name
	A.(CH₃CH₂)₂NCH₃ = N-Ethyl-N-methylethanamine
	B.(CH₃)₃CNH₂ = 2-methylpropan-2-amine
	C.CH₃NHCH (CH₃)₂ = N-Methylpropan-2-amine
	D.(CH₃)₂CHNH₂ = 2, 2-Dimethyl-N-propanamine

Ans: (CH₃CH₂)₂NCH₃ = N-Ethyl-N-methylethanamine

Q5.	The most convenient method to prepare primary (i Amine) amine containing one carbon atom less is
	A.Gabriel phthalmidie synthesis
	B.Reductive amination of aldehydes
	C.Hofmann bromamide reaction
	D.Reduction of isonitriles

Ans: Hofmann bromamide reaction

Q6.	When excess of ethyl iodide is treated with ammonia, the product is
	A.ethylamine
	B.diethylamine
	C.triethylamine
	D.tetrathylammonium iodide

Ans: tetrathylammonium iodide

Q7.	Amides may be converted into amines by a reaction named after
	A.Hofmann Bromide
	B.Claisen
	C.Perkin
	D.Kekule

Ans: Hofmann Bromide

Q8.	Reduction of CH₃CH₂NC with hydrogen in presence of Ni or Pt as catalvst gives
	A.CH₃CH₂NH₂
	B.CH₃CH₂NHCH₃
	C.CH₃CH₂NHCH₂CH₃
	D.(CH₃)₃N

Ans: CH₃CH₂NHCH₃

Q9.	Secondary amines can be prepared by
	A.reduction of nitro compounds
	B.oxidation of N-substituted amides
	C.reduction of isonitriles
	D.reduction of nitriles

Ans: reduction of isonitriles

Q10.	Which of the following amides will give ethylamine on reaction with sodium hypobromide?
	A.Butanamide
	B.Propanamide
	C.Acetamide
	D.Benzamide

Ans: Propanamide

Q11.	Benzoic acid is treated with SOCl₂ and the product (X) formed is reacted with ammonia to give (Y). (Y) on reaction with Br₂ and KOH gives (Z). (Z) in the reaction is
	A.aniline
	B.chlorobenzene
	C.benzamide
	D.benzoyl chloride

Ans: aniline

Q12.	Which one of the following reducing agents is likely to be most effective in bringing about the following change?
	A.H₂-Ni
	B.NaBH₄
	C.LiAlH₄ ether
	D.Na-AIcohol

Ans: LiAlH₄ ether

Q13.	Amine that cannot be prepared by Gabricl-Phthalmidie synthesis is
	A.aniline
	B.benzyl amine
	C.methyl amine
	D.iso-butylamine

Ans: aniline

Q14.	What is the end product in the following sequence of reactions?
	A.Aniline
	B.Phenol
	C.Benzene
	D.Benzenediazxonium chloride

Ans: Aniline

Q15.	Tertiary amines have lowest boiling points amongst isomeric amines because
	A.they have highest molecular mass
	B.they do not form hydrogen bonds
	C.they are more polar in nature
	D.they are most basic in nature

Ans: they do not form hydrogen bonds

Q16.	Which of the following amines will give carbylatnine reaction?
	A.(C₂H₅)₃N
	B.(C₂H₅)₂NH
	C.C₂H₅NH₂
	D.C₃H₇NHC₂H₃5

Ans: C₂H₅NH₂

Q17.	in the above reaction is
	A.CH₃CH₂CH₂NHCOCH₃
	B.CH₃CH₂CH₂NH₂
	C.CH₃CH₂CH₂CONHCH₃
	D.CH₃CH₂CH₂CONHCOCH₃

Ans: CH₃CH₂CH₂NHCOCH₃

Q18.	The end product Z of the reaction
	A.propanenitrile
	B.triethylamine
	C.diethylamine
	D.propylamine

Ans: propanenitrile

Q19.	Primary and secondary amines are distinguished by
	A.Br₂/ROH
	B.HClO
	C.HNO₂
	D.NH₃

Ans: HNO₂

Q20.	Arrange the following compounds in increasing order of basicity: CH₃NH₂, (CH₃)₂ NH, NH₃, C₆H₅NH₂
	A.C₆H₅NH₂ < NH₃ < (CH₃)₂NH < CH₃NH₂
	B.CH₃NH₂ < (CH₃)₂NH < NH₃ < C₆H₅NH₂
	C.C₆H₅NH₂ <NH₃ < CH₃NH₂<(CH₃)₂NH
	D.(CH₃)₂NH < CH₃NH₂ <NH₃ < C₆H₅NH₂