MCQ Questions for Class 12 Physics Chapter 4 Moving Charges and Magnetism Part-2 with Answers

Moving Charges and Magnetism Part-2 Class 12 Physics MCQs Questions with Answers

Check the below NCERT MCQ Questions for Class 12 Physics Chapter 4 Moving Charges and Magnetism Part-2 with Answers Pdf free download. MCQ Questions for Class 12 Physics with Answers were prepared based on the latest exam pattern. We have Provided Moving Charges and Magnetism Part-2 Class 12 Physics MCQs Questions with Answers to help students understand the concept very well.

Class 12 Physics Chapter 4 Quiz

Class 12 Physics Chapter 4 MCQ Online Test

You can refer to NCERT Solutions for Class 12 Physics Chapter 4 Moving Charges and Magnetism Part-2 to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

Moving Charges and Magnetism Part-2 Class 12 Physics MCQ online test

Q1.	When charged particle enters-a uniform magnetic field, its K.E.:
	A.remains constant
	B.increases
	C.decreases
	D.becomes zero

Ans: remains constant

Q2.	To convert galvanometer into voltmeter one should connect :
	A.high resistance in series with galvanometer
	B.low resistance in series with galvanometer
	C.high resistance in parallel with galvanometer
	D.low resistance in parallel with galvanometer

Ans: high resistance in series with galvanometer

Q3.	A charge q moves in a region, where electric field E and magnetic field B both exist, then force on it is :
	A.\(\vec{F}\) = q(\(\vec{v}\)×\(\vec{B}\))
	B.\(\vec{F}\) = q{\(\vec{E}\)×(\(\vec{v}\) × \(\vec{B}\))}
	C.\(\vec{F}\) = q(\(\vec{E}\) + (\(\vec{B}\) × \(\vec{v}\))
	D.\(\vec{F}\) = q(\(\vec{B}\) + (\(\vec{E}\) ×\(\vec{v}\))

Ans: \(\vec{F}\) = q{\(\vec{E}\)×(\(\vec{v}\) × \(\vec{B}\))}

Q4.	Isoclinic lines are the lines joining places with :
	A.equal dip
	B.equal declination
	C.equal dip and declination
	D.None of these

Ans: equal dip

Q5.	Two identical bar magnets each of dipole moment p and length I are perpendicular to each other as shown in Fig. The dipole moment of the combination is:
	A.√2 p
	B.\(\frac{p}{√2}\)
	C.P
	D.2p

Ans: √2 p

Q6.	The most suitable metal for making permanent magnets is :
	A.iron
	B.steel
	C.copper
	D.aluminium

Ans: steel

Q7.	The SI unit of magnetic dipole moment is’
	A.Ampere
	B.Ampere metre²
	C.Tesla
	D.None of these

Ans: Ampere metre²

Q8.	Earth’s magnetism was discovered by:
	A.Gauss
	B.Oersted
	C.Ampere
	D.Gilbert

Ans: Gilbert

Q9.	According to Gauss’s theorem in magnetism, surface integral of magnetic field intensity over a surface (closed or open) is always:
	A.-1
	B.1
	C.0
	D.infinity

Ans: 0

Q10.	Tesla is a unit of:
	A.electric flux
	B.magnetic flux
	C.magnetic field
	D.electric field

Ans: magnetic field

Q11.	10 eV electron is circulating in a plane at right angle to a uniform field of magnetic induction 10^-1 Wb/m² (1G). The orbital radius of electron is:
	A.12 cm
	B.16 cm
	C.11 cm
	D.18 cm

Ans: 11 cm

Q12.	A cyclotron can be used to produce high energy:
	A.neutrons
	B.deutrons
	C.β particles
	D.α partifcles

Ans: α partifcles

Q13.	The radius of the trajectory of a charged particle in a uniform magnetic field is proportional to the:
	A.charge on the particle
	B.energy of the particle
	C.momentum of the particle
	D.all the above

Ans: momentum of the particle

Q14.	The force \(\vec{F}\) experienced by a particle of charge q moving with velocity \(\vec{v}\) in a magnetic field \(\vec{B}\) is given by,
	A.\(\vec{F}\) = q(\(\vec{F}\) × \(\vec{B}\))
	B.\(\vec{F}\) = q(\(\vec{B}\) × (\(\vec{b}\))
	C.\(\vec{F}\) = q(\(\vec{v}\) × (\(\vec{B}\))
	D.\(\vec{F}\) = q(\(\vec{v}\) × \(\vec{B}\))

Ans: \(\vec{F}\) = q(\(\vec{F}\) × \(\vec{B}\))

Q15.	The torque acting on a magnetic dipole of moment \(\vec{p_m}\) when placed in a magnetic field \(\vec{B}\) is:
	A.p_mB
	B.\(\vec{p_m}\) × \(\vec{B}\)
	C.\(\vec{p_m}\)\(\vec{B}\)
	D.\(\frac{p_m}{B}\)

Ans: \(\vec{p_m}\) × \(\vec{B}\)

Q16.	In thomson spectrograph \(\vec{E}\) ⊥ \(\vec{B}\), then velocity of electron beam will be:
	A.\|\(\vec{E}\)\|/\|\(\vec{B}\)\|
	B.\(\vec{E}\) × \(\vec{B}\)
	C.\|\(\vec{B}\)\|/\|\(\vec{E}\)\|
	D.E² / B²