MCQ Questions | Class 10 Maths Chapter 5

MCQ Questions | Class 10 Maths Chapter 5 | Arithmetic Progressions with Answers 

MCQ Questions for Class10 Maths Chapter 5 Arithmetic Progressions

MCQ | Arithmetic Progressions Class 10 | Sat A

Check the below NCERT MCQ Questions for Class 10 Maths Chapter 5 Arithmetic Progressions with Answers Pdf free download. MCQ Questions for Class 10 Maths with Answers were prepared based on the latest exam pattern. We have Provided Arithmetic Progressions Class 10 Maths MCQs Questions with Answers to help students understand the concept very well.

Objective Question | NCERT Maths Class 10

NCERT Solutions Class 10 Maths
Book: National Council of Educational Research and Training (NCERT)
Board: Central Board of Secondary Education (CBSE)
Class: 10th
Subject: Maths
Chapter: 5
Chapters Name: Arithmetic Progressions
Medium: English

Ncert Solutions for Class 10 Maths | Objective Type Questions


You can refer to NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.
Arithmetic Progressions | Class 10 Maths | NCERT Solutions
Q1. The nth term of an A.P. is given by an = 3 + 4n. The common difference is
A. 7
B. 3
C. 4
D. 1
Ans: 4
Explaination:Reason: We have an = 3 + 4n
∴ an+1 = 3 + 4(n + 1) = 7 + 4n
∴ d = an+1 – an
= (7 + 4n) – (3 + 4n)
= 7 – 3
= 4

Q2. If p, q, r and s are in A.P. then r – q is
A. s – p
B. s – q
C. s – r
D. none of these
Ans: s – r
Explaination:Reason: Since p, q, r, s are in A.P.
∴ (q – p) = (r – q) = (s – r) = d (common difference)

Q3. If the sum of three numbers in an A.P. is 9 and their product is 24, then numbers are
A. 2, 4, 6
B. 1, 5, 3
C. 2, 8, 4
D. 2, 3, 4
Ans: 2, 3, 4
Explaination:Reason: Let three numbers be a – d, a, a + d
∴ a – d +a + a + d = 9
⇒ 3a = 9
⇒ a = 3
Also (a – d) . a . (a + d) = 24
⇒ (3 -d) .3(3 + d) = 24
⇒ 9 – d² = 8
⇒ d² = 9 – 8 = 1
∴ d = ± 1
Hence numbers are 2, 3, 4 or 4, 3, 2
Q4. The (n – 1)th term of an A.P. is given by 7,12,17, 22,… is
A. 5n + 2
B. 5n + 3
C. 5n – 5
D. 5n – 3
Ans: 5n – 3
Explaination:Reason: Here a = 7, d = 12-7 = 5
∴ an-1 = a + [(n – 1) – l]d = 7 + [(n – 1) -1] (5) = 7 + (n – 2)5 = 7 + 5n – 10 = 5M – 3
Q5. The nth term of an A.P. 5, 2, -1, -4, -7 … is
A. 2n + 5
B. 2n – 5
C. 8 – 3n
D. 3n – 8
Ans: 8 – 3n
Explaination:Reason: Here a = 5, d = 2 – 5 = -3
an = a + (n – 1)d = 5 + (n – 1) (-3) = 5 – 3n + 3 = 8 – 3n

Q6. The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is
A. -955
B. -945
C. -950
D. -965
Ans: -955
Explaination:Reason: Here l = -1000, d = -10 – (-5) = -10 + 5 = – 5
∴ 10th term from the end = l – (n – 1 )d = -1000 – (10 – 1) (-5) = -1000 + 45 = -955

Q7. Find the sum of 12 terms of an A.P. whose nth term is given by an = 3n + 4
A. 262
B. 272
C. 282
D. 292
Ans: 262
Explaination:Reason: Here an = 3n + 4
∴ a1 = 7, a2 – 10, a3 = 13
∴ a= 7, d = 10 – 7 = 3
∴ S12 = \(\frac{12}{2}\)[2 × 7 + (12 – 1) ×3] = 6[14 + 33] = 6 × 47 = 282

Q8. The sum of all two digit odd numbers is
A. 2575
B. 2475
C. 2524
D. 2425
Ans: 2475
Explaination:Reason: All two digit odd numbers are 11,13,15,… 99, which are in A.P.
Since there are 90 two digit numbers of which 45 numbers are odd and 45 numbers are even
∴ Sum = \(\frac{45}{2}\)[11 + 99] = \(\frac{45}{2}\) × 110 = 45 × 55 = 2475

Q9. The (n – 1)th term of an A.P. is given by 7,12,17, 22,… is
A. 5n + 2
B. 5n + 3
C. 5n – 5
D. 5n – 3
Ans: 5n – 3
Q10. The number of two digit numbers divisible by 5 is
A. 19
B. 18
C. 16
D. 17
Ans: 18
Q11. What is the sum of the first 50 multiples of 3?​
A. 3255
B. 3825
C. 4325
D. 4455
Ans: 3825
Q12. If 7th and 13th terms of an A.P. be 34 and 64, respectively, then it's 18th term is :
A. 87
B. 88
C. 89
D. 90
Ans: 89
Q13. The weights of 11 students selected for a team are noted in ascending order and are in A. P. The lowest value is 45 Kg, and the middle value is 55 Kg. What is the difference between the two values placed consecutively ?
A. 4
B. 2
C. 6
D. 3
Ans: 2
Q14. Find the sum of 12 terms of an A.P. whose nth term is given by an = 3n + 4
A. 262
B. 272
C. 282
D. 292
Ans: 262
Q15. The sum of first n odd natural numbers is
A. 2n²
B. 2n + 1
C. 2n – 1
D.
Ans:
Explaination:Reason: Required Sum = 1 + 3 + 5 + … + upto n terms.
Here a = 1, d = 3 – 1 = 2
Sum = \(\frac{n}{2}\)[2 × 1 + (n – 1) × 2] = \(\frac{n}{2}\)[2 + 2n – 2] = \(\frac{n}{2}\) × 2n = n²Reason: All two digit odd numbers are 11,13,15,… 99, which are in A.P.
Since there are 90 two digit numbers of which 45 numbers are odd and 45 numbers are even
∴ Sum = \(\frac{45}{2}\)[11 + 99] = \(\frac{45}{2}\) × 110 = 45 × 55 = 2475
Q16. The number of multiples lie between n and n² which are divisible by n is
A. n + 1
B. n
C. n – 1
D. n – 2
Ans: n – 2
Explaination:Reason: Multiples of n from 1 to n² are n × 1, n × 2, n × 3, …, m× n
∴ There are n numbers
Thus, the number of mutiples of n which lie between n and n² is (n – 2) leaving first and last in the given list: Total numbers are (n – 2).
Q17. If a, b, c, d, e are in A.P., then the value of a – 4b + 6c – 4d + e is
A. 0
B. 1
C. -1.
D. 2
Ans:
Explaination:Reason: Let common difference of A.P. be x
∴ b = a + x, c = a + 2x, d = a + 3x and e = a + 4x
Given equation n-4b + 6c-4d + c
= a – 4(a + x) + 6(A + 2r) – 4(n + 3x) + (o + 4.v)
= a – 4a – 4x + 6a + 12x – 4a – 12x + a + 4x = 8a – 8a + 16x – 16x = 0

Q18. nth term of the sequence a, a + d, a + 2d,… is
A. a + nd
B. a – (n – 1)d
C. a + (n – 1)d
D. n + nd
Ans: a + nd
Explaination:Reason: an = a + (n – 1)d

Q19. The 10th term from the end of the A.P. 4, 9,14, …, 254 is
A. 209
B. 205
C. 214
D. 213
Ans: 29
Explaination:Reason: Here l – 254, d = 9-4 = 5
∴ 10th term from the end = l – (10 – 1 )d = 254 -9d = 254 = 9(5) = 254 – 45 = 209

Q20. If 2x, x + 10, 3x + 2 are in A.P., then x is equal to
A. 0
B. 2
C. 4
D. 6
Ans: 6
Explaination:Reason: Since 2x, x + 10 and 3x + 2 are in A.P.
∴ 2(x + 10) = 2x + (3x + 2)
⇒ 2x + 20 – 5x + 2
⇒ 2x – 5x = 2 – 20
⇒ 3x = 18
⇒ x = 6

CBSE Solutions | Ncert Solutions Maths Class 10


NCERT Solutions | 10th Maths Guide


NCERT | Class 10 Maths Solution

Ncert Solutions for Class 10 Maths


Ncert Solutions for Class 10 Maths Chapter 1


    MCQ Questions for Class 10 Maths Chapter 1 Real Numbers Sat A
    MCQ Questions for Class 10 Maths Chapter 1 Real Numbers Sat B
    MCQ Questions for Class 10 Maths Chapter 1 Real Numbers Sat C
    MCQ Questions for Class 10 Maths Chapter 1 Real Numbers Sat D

Ncert Solutions for Class 10 Maths Chapter 2


    MCQ Questions for Class 10 Maths Chapter 2 Polynomials Sat A
    MCQ Questions for Class 10 Maths Chapter 2 Polynomials Sat B
    MCQ Questions for Class 10 Maths Chapter 2 Polynomials Sat C

Ncert Solutions for Class 10 Maths Chapter 3


    MCQ Questions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Sat A
    MCQ Questions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Sat B
    MCQ Questions for Class 10 Maths Chapter 3 Pair of Linear Equations in Two Variables Sat C

Ncert Solutions for Class 10 Maths Chapter 4


    MCQ Questions for Class 10 Maths Chapter 4 Quadratic Equations Sat A
    MCQ Questions for Class 10 Maths Chapter 4 Quadratic Equations Sat B
    MCQ Questions for Class 10 Maths Chapter 4 Quadratic Equations Sat C

Ncert Solutions for Class 10 Maths Chapter 5


    MCQ Questions for Class 10 Maths Chapter 5 Arithmetic Progressions Sat A
    MCQ Questions for Class 10 Maths Chapter 5 Arithmetic Progressions Sat B
    MCQ Questions for Class 10 Maths Chapter 5 Arithmetic Progressions Sat C

Ncert Solutions for Class 10 Maths Chapter 6


    MCQ Questions for Class 10 Maths Chapter 6 Triangles Sat A
    MCQ Questions for Class 10 Maths Chapter 6 Triangles Sat B

Ncert Solutions for Class 10 Maths Chapter 7


    MCQ Questions for Class 10 Maths Chapter 7 Coordinate Geometry Sat A
    MCQ Questions for Class 10 Maths Chapter 7 Coordinate Geometry Sat B

Ncert Solutions for Class 10 Maths Chapter 8


    MCQ Questions for Class 10 Maths Chapter 8 Introduction to Trigonometry Sat A
    MCQ Questions for Class 10 Maths Chapter 8 Introduction to Trigonometry Sat B
    MCQ Questions for Class 10 Maths Chapter 8 Introduction to Trigonometry Sat C

Ncert Solutions for Class 10 Maths Chapter 9


    MCQ Questions for Class 10 Maths Chapter 9 Some Applications of Trigonometry Sat A
    MCQ Questions for Class 10 Maths Chapter 9 Some Applications of Trigonometry Sat B

Ncert Solutions for Class 10 Maths Chapter 10


    MCQ Questions for Class 10 Maths Chapter 10 Circles Sat A
    MCQ Questions for Class 10 Maths Chapter 10 Circles Sat B

Ncert Solutions for Class 10 Maths Chapter 11


    MCQ Questions for Class 10 Maths Chapter 11 Constructions Sat A
    MCQ Questions for Class 10 Maths Chapter 11 Constructions Sat B

Ncert Solutions for Class 10 Maths Chapter 12


    MCQ Questions for Class 10 Maths Chapter 12 Areas Related to Circles Sat A
    MCQ Questions for Class 10 Maths Chapter 12 Areas Related to Circles Sat B

Ncert Solutions for Class 10 Maths Chapter 13


    MCQ Questions for Class 10 Maths Chapter 13 Surface Areas and Volumes Sat A
    MCQ Questions for Class 10 Maths Chapter 13 Surface Areas and Volumes Sat B
    MCQ Questions for Class 10 Maths Chapter 13 Surface Areas and Volumes Sat C

Ncert Solutions for Class 10 Maths Chapter 14


    MCQ Questions for Class 10 Maths Chapter 14 Statistics Sat A
    MCQ Questions for Class 10 Maths Chapter 14 Statistics Sat B

Ncert Solutions for Class 10 Maths Chapter 15


    MCQ Questions for Class 10 Maths Chapter 15 Probability Sat A
    MCQ Questions for Class 10 Maths Chapter 15 Probability Sat B

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