MCQ Questions | Class 10 Maths Chapter 7 | Coordinate Geometry with Answers

MCQ | Coordinate Geometry Class 10 | Sat B

Check the below NCERT MCQ Questions for Class 10 Maths Chapter 7 Coordinate Geometry with Answers Pdf free download. MCQ Questions for Class 10 Maths with Answers were prepared based on the latest exam pattern. We have Provided Coordinate Geometry Class 10 Maths MCQs Questions with Answers to help students understand the concept very well.

Objective Question | NCERT Maths Class 10

NCERT Solutions Class 10 Maths
Book:	National Council of Educational Research and Training (NCERT)
Board:	Central Board of Secondary Education (CBSE)
Class:	10th
Subject:	Maths
Chapter:	7
Chapters Name:	Coordinate Geometry
Medium:	English

Ncert Solutions for Class 10 Maths | Objective Type Questions

You can refer to NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

Coordinate Geometry | Class 10 Maths | NCERT Solutions

Q1.	The perimeter of a triangle with vertices (0, 4) (0, 0) and (3, 0) is:
	A. 15
	B. 12
	C. 8
	D. 10

Ans: 12

Q2.	The horizontal and vertical lines drawn to determine the position of a point in a Cartesian plane are called
	A. Intersecting lines
	B. Transversals
	C. Perpendicular lines
	D. X-axis and Y-axis

Ans: X-axis and Y-axis

Q3.	If A and B are the points (-6, 7) and (-1, -5) respectively, then the distance 2AB is equal to
	A. 26
	B. 169
	C. 13
	D. 238

Ans: 26

Q4.	he ratio in which the x-axis divides the segment joining A(3,6) and B(12,-3) is
	A. 1:2
	B. -2:1
	C. 2:1
	D. -1:-1

Ans: 2:1

Q5.	The distance between the points (– 1, – 5) and (– 6, 7) is
	A. 144 units
	B. 13 units
	C. 12 units
	D. 169 units

Ans: 13 units

Q6.	The area of the triangle whose vertices are A(1, 2), B(-2, 3) and C(-3, -4) is
	A. 11
	B. 22
	C. 33
	D. 21

Ans: 11
Explaination: Reason: Required area= \(\frac{1}{2}\)[1(3 + 4) -2(-4 – 2) -3(2 – 3)]
= \(\frac{1}{2}\)[7 + 12 + 3]
= \(\frac{1}{2}\) × 22 = 11

Q7.	If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is
	A. -7 or -1
	B. -7 or 1
	C. 7 or 1
	D. 7 or -1

Ans: 7 or -1
Explaination: Reason: We have \(\sqrt{(x-3)^{2}+(-1-2)^{2}}=5\)
⇒ (x – 3)² + 9 = 25
⇒ x² – 6x + 9 + 9 = 25
⇒ x² -6x – 7 = 0
⇒ (x – 7)(x + 1) = 0
⇒ x = 7 or x = -1

Q8.	The area of the triangle formed by the points A(-1.5, 3), B(6, -2) and C(-3, 4) is
	A. 0
	B. 1
	C. 2
	D. 3/2

Ans: 0
Explaination: Reason: Area of ΔABC = \(\frac{1}{2}\) [-1.5(-2 – 4) + 6(4 – 3) + (-3) (3 + 2)] = \(\frac{1}{2}\) [9 + 6 – 15] = 0. It is a straight line.

Q9.	If the points P(1, 2), B(0, 0) and C(a, b) are collinear, then
	A. 2a = b
	B. a = -b
	C. a = 2b
	D. a = b

Ans: 2a = b
Explaination: Reason: Area of ΔPBC = 0
⇒ \(\frac{1}{2}\)[1(0 – b) + 0(6 – 1) + a(2 – 0)] = 0
⇒ \(\frac{1}{2}\)[-6 + 2a] = 0
⇒ -b + 2a = 0
∴ 2a = b

Q10.	If the segment joining the points (a, b) and (c, d) subtends a right angle at the origin, then
	A. ac – bd = 0
	B. ac + bd = 0
	C. ab + cd = 0
	D. ab – cd= 0

Ans: ac + bd =

Explaination:

Let A {a, b), B(c, d), 0(0, 0)
∴ ∠AOB = 90°
⇒ AB² = AO² + BO²
(c – a)² + (d- b)² = a² + b² + c² + d²
⇒ ac + bd = 0

Q11.	The points (k + 1, 1), (2k + 1, 3) and (2k + 2, 2k) are collinear if
	A. k = -1, 2
	B. k=\(\frac{1}{2}\),2
	C. k = 2, 1
	D. k = –\(\frac{1}{2}\),2

Ans: k = –\(\frac{1}{2}\),2

Explaination:

∵ Points are collinear.
∴ (k + 1) (3 – 2k) + (2k + 1) (2k- 1) + (2k + 2) (1 – 3) = 0
⇒ 3k + 3 – 2k² – 2k + 4k² – 1 -4k – 4 = 0
⇒ 2k² – 3k – 2 = 0
⇒ 2k² – 4k + k – 2 = 0
⇒ 2k(k – 2) + 1(k – 2) = 0
⇒ (2k + 1) (k – 2) = 0
k = –\(\frac{1}{2}\), k = 2

Q12.	The area of the triangle with vertices at the points (a, b + c), (b, c + a) and (c, a + b) is
	A. (a + b + c) sq. units
	B. (a + b – c) sq. units
	C. (a – b + cj sq. units
	D. 0

Ans:

Explaination:

Using formula for area of triangle, we get
Area = zero.
Area of triangle
= \(\frac{1}{2}\)| a(c + a- a-b) + b(a+ b- b-c) + c(b + c- c-a) |
= \(\frac{1}{2}\) |ac – ab + ba – bc + cb – ca| = 0

Q13.	The distance between the points (3,4) and (8,-6) is
	A. 2√5 units
	B. 3√5 units
	C. √5 units
	D. 5√5 units

Ans: 5√5 units

Q14.	Origin divides the join of points (1,1) and (2,2) externally in the ratio
	A. 1:2
	B. 1:-2
	C. -1:-2
	D. -1:2

Ans: 1:2

Q15.	The values of x and y, if the distance of the point (x,y) from (-3,0) as well as from (3,0) is 4 are
	A. x = 1, y = 7
	B. x = 2, y = 7
	C. x = 0, y = – √7
	D. x = 0, y = ± √7

Ans: x = 0, y = ± √7

Q16.	The distance of the point P(6,-6) from the origin is equal to
	A. 3 √4 units
	B. 8 units
	C. 6 √2 units
	D. 3 units

Ans: 6 √2 units

Q17.	The ratio in which (4,5) divides the line segment joining the points (2,3) and (7,8) is
	A. 2:3
	B. -3:2
	C. 3:2
	D. -2:3

Ans: 2:3

Q18.	The points (3, 2), (0, 5), (-3, 2) and (0, -1) are the vertices of a quadrilateral. Which quadrilateral is it?
	A. Rectangle
	B. Square
	C. Parallelogram
	D. Rhombus

Ans: Square

Q19.	0
	A.0
	B.0
	C.0
	D.0

Ans: 0

Q20.	0
	A.0
	B.0
	C.0
	D.0

Ans: 0

CBSE Solutions | Ncert Solutions Maths Class 10

NCERT Solutions | 10th Maths Guide

NCERT | Class 10 Maths Solution

Ncert Solutions for Class 10 Maths

MCQ Questions | Class 10 Maths Chapter 7

MCQ Questions | Class 10 Maths Chapter 7 | Coordinate Geometry with Answers

MCQ | Coordinate Geometry Class 10 | Sat B

Objective Question | NCERT Maths Class 10

Ncert Solutions for Class 10 Maths | Objective Type Questions

Coordinate Geometry | Class 10 Maths | NCERT Solutions

CBSE Solutions | Ncert Solutions Maths Class 10

NCERT Solutions | 10th Maths Guide

NCERT | Class 10 Maths Solution

Ncert Solutions for Class 10 Maths

Ncert Solutions for Class 10 Maths Chapter 1

Ncert Solutions for Class 10 Maths Chapter 2

Ncert Solutions for Class 10 Maths Chapter 3

Ncert Solutions for Class 10 Maths Chapter 4

Ncert Solutions for Class 10 Maths Chapter 5

Ncert Solutions for Class 10 Maths Chapter 6

Ncert Solutions for Class 10 Maths Chapter 7

Ncert Solutions for Class 10 Maths Chapter 8

Ncert Solutions for Class 10 Maths Chapter 9

Ncert Solutions for Class 10 Maths Chapter 10

Ncert Solutions for Class 10 Maths Chapter 11

Ncert Solutions for Class 10 Maths Chapter 12

Ncert Solutions for Class 10 Maths Chapter 13

Ncert Solutions for Class 10 Maths Chapter 14

Ncert Solutions for Class 10 Maths Chapter 15

NCERT SOLUTIONS

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