NCERT Solutions | Class 11 Chemistry Chapter 7

NCERT Solutions | Class 11 Chemistry Chapter 7 | Equilibrium 

CBSE Solutions | Chemistry Class 11

Check the below NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium Pdf free download. NCERT Solutions Class 11 Chemistry  were prepared based on the latest exam pattern. We have Provided Equilibrium Class 11 Chemistry NCERT Solutions to help students understand the concept very well.

NCERT | Class 11 Chemistry

NCERT Solutions Class 11 Chemistry

Book:	National Council of Educational Research and Training (NCERT)
Board:	Central Board of Secondary Education (CBSE)
Class:	11th
Subject:	Chemistry
Chapter:	7
Chapters Name:	Equilibrium
Medium:	English

Equilibrium | Class 11 Chemistry | NCERT Books Solutions

You can refer to MCQ Questions for Class 11 Chemistry Chapter 7 Equilibrium to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

NCERT Exercises

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 1.

A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The
volume of the container is suddenly increased.
(a) What is the initial effect of the change on vapour pressure?
(b) How do rates of evaporation and condensation change initially?
(c) What happens when equilibrium is restored finally and what will be the final vapour pressure?

Solution.

(a) Vapour pressure decreases since equilibrium is disturbed and the rate of condensation falls considerably.
(b) Rate of evaporation increases while that of condensation falls initially.
(c) On restoration of the equilibrium again, the vapour pressure becomes the same.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 2.

What is K_c for the following equilibrium when the equilibrium concentration of each substance is : [SO₂] = 0.60 M, [O₂] = 0.82 M and [SO₂] = 1.90 M
2SO_2(g) + O_2(g) ⇌ 2SO_3(g)

Solution.

2SO_2(g) + O_2(g) ⇌ 2SO_3(g)
Applying law of chemical equilibrium,
\({ K }_{ c }=\frac { { \left[ { SO }_{ 3 } \right] }^{ 2 } }{ { \left[ { SO }_{ 2 } \right] }^{ 2 }\left[ { O }_{ 2 } \right] } =\frac { { (1.9) }^{ 2 } }{ { (0.6) }^{ 2 }{ (0.82) } } =12.229L\quad { mol }^{ -1 } \)

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 3.

At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms. I_2(g) ⇌ 2l_(g)Calculate Kp for the equilibrium.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 4.

Write the expression for the equilibrium constant, K_c for each of the following reactions:

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 5.

Find out the value of K_cof each of the following equilibria from the value of Kp:

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 6.

For the following equilibrium, K_c= 6.3 x 10¹⁴ at 1000 K. NO_(g) + O_3(g) ⇌ NO_{2(g) + O2(g)} the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is K_c, for the reverse reaction?

Solution.

NO_(g) + O_3(g) ⇌ NO_2(g) + O_2(g)
\({ K }_{ c }=\frac { \left[ { NO }_{ 2 } \right] \left[ { O }_{ 2 } \right] }{ \left[ NO \right] \left[ { O }_{ 3 } \right] } =6.3\times { 10 }^{ 14 }\)
For the reverse reaction,
\({ K }_{ c }^{ ` }=\frac { \left[ NO \right] \left[ { O }_{ 3 } \right] }{ \left[ { NO }_{ 2 } \right] \left[ { O }_{ 2 } \right] } =\frac { 1 }{ { K }_{ c } } =\frac { 1 }{ 6.3\times { 10 }^{ 14 } } =1.587\times { 10 }^{ -15 }\)

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 7.

Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression.

Solution.

For the concentration of pure solid or pure liquid,
\(Molar\quad conc.=\frac { Moles\quad of\quad the\quad substance }{ Volume\quad of\quad the\quad substance } \)
\(=\frac { Mass/Molar\quad mass }{ Volume } =\frac { Mass }{ Volume } \times \frac { 1 }{ Molar\quad mass } =\frac { Density }{ Molecular\quad mass } \)
Since density of pure solid or liquid is constant at constant temperature and molar mass is also constant therefore, their molar concentrations are constant and are included in the equilibrium constant.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 8.

Reaction between N₂ and O₂ takes place as follows:
2N_2(g) + O_2(g) ⇌ 2N₂O_(g)
If a mixture of 0.482 mol of N₂ and 0.933 mol of O₂ is placed in a 10 L reaction vessel and allowed to form N₂O at a temperature for which K_c = 2.0 x 10^-37, determine the composition of equilibrium mixture.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 9.

Nitric oxide reacts with Br2 and gives nitrosyl bromide as reaction given below:
2NO_(g) + Br_2(g) ⇌ 2NOBr_(g) When 0.087 mol of NO and 0.0437 mol of Br₂ are mixed in a closed container at constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. Calculate equilibrium amount of NO and Br2.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 10.

At 450 K, K_p = 2.0 x 10¹⁰.bar for the given reaction at equilibrium.
2SO_2(g)+ O_2(g) ⇌ 2SO_3(g)
What is K_c at this temperature?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 11.

A sample of HI_(g) is placed in a flask at a pressure of 0.2 atm. At equilibrium partial pressure of HI_(g) is 0.04 atm. What is K_p for the given equilibrium ?
2HI_(g) \(\rightleftharpoons \) H_2(g) + I_2(g)

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 12..

AA mixture of 1.57 mol of N₂, 1.92 mol of H₂ and 8.13 mol of NH₃ is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant K_c for the reaction given as follows :
N_2(g) + 3H_2(g) \(\rightleftharpoons \) 2NH_3(g) is 1.7 × 10^-2.
Is this reaction at equilibrium ? If not, what is the direction of net reaction ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 13.

The equilibrium constant expression for a gas reaction is,

Write the balanced chemical equation corresponding to this expression.

Solution.

Balanced chemical equation for the reaction is
4 NO_(g) + 6 H₂O_(g) \(\rightleftharpoons \) 4NH_3(g) + 5 O_2(g)

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 14.

If 1 mole of H₂O and 1 mole of CO are taken in a 10 litre vessel and heated to 725 K, at equilibrium point 40 percent of water (by mass) reacts with carbon monoxide according to equation,
H₂O_(g) + CO_(g) \(\rightleftharpoons \) H_2(g) + CO_2(g)
Calculate the equilibrium constant for the reaction.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 15.

At 700 K, the equilibrium constant for the reaction H_2(g) + I_2(g) \(\rightleftharpoons \) 2HI_(g) is 54.8. If 0.5 mol L^-1 of HI_(g) is present at equilibrium at 700 K, what are the concentration of H₂(g) and I_2(g) ? Assume that we initially started with HI_(g) and allowed it to reach equilibrium at 700 K.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 16.

What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M ?
2ICl_(g) \(\rightleftharpoons \) I_2(g) + Cl_2(g) ; K_c = 0.14

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 17.

K_p = 0.04 atm at 898 K for the equilibrium shown below. What is the equilibrium concentration of C₂H₆ when it is placed in a flask at 4 atm pressure and allowed to come to equilibrium.
C₂H_6(g) \(\rightleftharpoons \) C₂H_4(g) + H_2(g)

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 18.

The ester, ethyl acetate is formed by the reaction of ethanol and acetic acid and the equilibrium is represented as :
CH₃COOH_l + C₂H₅OH_l \(\rightleftharpoons \) CH₃COOC₂H_5l + H₂O_l
(i) Write the concentration ratio (concentration quotient) Q for this reaction. Note that water is not in excess and is not a solvent in this reaction.
(ii) At 293 K, if one starts with 1.000 mol of acetic acid and 0.180 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.
(iii) Starting with 0.50 mol of ethanol and 1.000 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate
is found after some time. Has equilibrium been reached ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 19.

A sample of pure PCl₅ was introduced into an evacuated vessel at 473 K. After equilibrium was reached, the concentration of PCl₅ was found to be 0.5 x 10^-1 mol L^-1. If K_c is 8.3 × 10^-3, what are the concentrations of PCl₃ and Cl₂ at the equilibrium ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 20.

One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and CO₂
FeO_(s) + CO_(g) \(\rightleftharpoons \) Fe_(s) + CO_2(g); K_p = 0.265 atm at 1050 K
What are the equilibrium partial pressures of CO and CO₂ at 1050 K if the initial pressures are :Pco = 1.4 atm and Pco₂ = 0.80 atm ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 21.

Equilibrium constant Kc for the reaction, N_2(g) + 3H_2(g) \(\rightleftharpoons \) 2NH_3(g) at 500 K is 0.061. At particular time, the analysis shows that the composition of the reaction mixture is : 3.0 mol L^-1 of N₂ , 2.0 mol L^-1 of H₂,0.50 mol L^-1 of NH₃. Is the reaction at equilibrium ? If not, in which direction does the reaction tend to proceed to reach the equilibrium ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 22.

Bromine monochloride (BrCl) decomposes into bromine and chlorine and reaches the equilibrium :
2BrCl_(g) \(\rightleftharpoons \) Br_2(g) + Cl_2(g)
For which K_c is 32 at 500 K. If initially pure BrCl is present at a concentration of 3.3× 10^-3 mol L^-1, what is its molar concentration in the mixture at equilibrium ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 23.

At 1127 K and 1 atmosphere pressure, a gaseous mixture of CO and CO₂ in equilibrium with solid carbon has 90.55% by mass.
C_(s) + CO_2(g) \(\rightleftharpoons \) 2CO_(g)
Calculate K_c for the reaction at the above temperature.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 24.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 25.

Does the number of moles of reaction products increase, decrease or remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume ?
(a) PCl_5(g) \(\rightleftharpoons \) PCl_3(g) + Cl₂
(b) CaO_(s) + CO_2(g) \(\rightleftharpoons \) CaCO_3(s)
(c) 3Fe_(s) + 4H₂O_(g) \(\rightleftharpoons \) Fe₃O_4(s) + 4H_2(g)

Solution.

Applying Le Chatelier’s principle, on decreasing the pressure, equilibrium shifts to the direction in which pressure increases, i.e., number of moles of gaseous substances is more. Thus, moles of reaction products will increase in reaction (a), decrease in reaction (b) and remain same (n_p, = n_r gaseous) in reaction (c).

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 26.

Which of the following reactions will get affected by increase in pressure ? Also mention whether the change will cause the reaction to go in the forward or backward direction.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 27.

The equilibrium constant for the following reaction is 1.6 x 10⁵ at 1024 K.
H_2(g) + Br_2(g) \(\rightleftharpoons \) 2HBr_(g)
Find the equilibrium pressure of all gases if 10.0 bar of HBr is introduced into a sealed container at 1024K.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 28.

Dihydrogen gas is obtained from the natural gas by partial oxidation with steam as per following endothermic reaction :
CH_4(g) + H₂O_(g) \(\rightleftharpoons \) CO_(g) + 3H_2(g)
(a) Write the expression for K_p for the above reaction
(b) How will the value of K_p and composition of equilibrium mixture be affected by :
(i) increasing the pressure
(ii) increasing the temperature
(iii) using a catalyst ?

Solution.

(b)

1. By Le Chatelier’s principle, on increasing pressure, equilibrium will shift in the backward direction where number of moles decreases.
2. As the given reaction is endothermic, by Le Chatelier ‘sprinciple, equilibrium will shift in the forward direction with increasing temperature.
3. Equilibrium composition will not be disturbed by the presence of catalyst but equilibrium will be attained quickly.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 29.

Describe the effect of :
(a) addition of H₂
(b) addition of CH₃OH
(c) removal of CO
(d) removal of CH₃OH on the equilibrium of the reaction:
2H_2(g) + CO_(g) \(\rightleftharpoons \) CH₃OH ?

Solution.

2H_2(g) + CO_(g) \(\rightleftharpoons \) CH₃OH Effect of
(a) addition of H₂ : The equilibrium will shift in the forward direction.
(b) addition of CH₃OH : The equilibrium will shift in the backward direction.
(c) removal of CO : The equilibrium will shift in the backward direction.
(d) removal of CH₃OH : The equilibrium will shift in the forward direction.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 30.

At 473 K, the equilibrium constant Kc for the decomposition of phosphorus pentachloride (PCl₅) is 8.3 × 10^-3. If decomposition proceeds as :
PCl_5(g) \(\rightleftharpoons \) PCl_3(g) + Cl_2(g) ; ∆H = + 124.0 kJ mol^-1
(a) Write an expression for K_c for the reaction.
(b) What is the value of K_c for the reverse reaction at the same temperature ?
What would be the effect on K_c if
(i) more PCl₅ is added
(ii) pressure is increased
(iii) the temperature is increased?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 31.

Dihydrogen gas used in Haber’s process is produced by reacting methane from natural gas with high temperature steam. The first stage of two stage reaction involves the formation of CO and H₂. In second stage, CO formed in first stage is reacted with more steam in water gas shift reaction.
CO_(g) + H₂O_(g) \(\rightleftharpoons \) CO_2(g) + H_2(g)
If a reaction vessel at 400°C is charged with an equimolar mixture of CO and steam so that pco = PH₂O = 4.0 bar, what will be the partial pressure of H₂ at equilibrium ? K_p = 0.1 at 400°C.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 32.

Predict which of the following will have appreciable concentration of reactants and products :
(a) Cl_2(g) \(\rightleftharpoons \) 2Cl_(g) ; K_c = 5 ×10^-39
(b) Cl_2(g) + 2NO_(g) \(\rightleftharpoons \) 2NOCl_(g) ; K_c = 3.7 × 10⁸
(c) Cl_2(g) + 2NO₂ (g) \(\rightleftharpoons \) 2NO₂Cl_(g) ; K_c = 1.8.

Solution.

(a) Since the value of K_c is very small
∴ There will be appreciable concentration of the reactants.
(b) Since K_c is very large.
∴ There will be appreciable concentration of the products.
(c) Since K_c = 1.8, the concentration of reactants and products will be in comparable amounts.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 33.

The value of K_c for the reaction 3O_2(g) \(\rightleftharpoons \) 2O_3(g) is 2.0 × 1 x 10^-50 at 25°C. If equilibrium concentration of O₂ in air at 25°C is 1.6 × 10^-2, what is the concentration of O₂ ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 34.

The reaction CO_(g) + 3H_2(g) \(\rightleftharpoons \) CH_4(g) + H₂O_(g) is at equilibrium at 1300 K in a 1L flask. It also contain 0.30 mol of CO, 0.10 mol of H₂ and 0.02 mol of H₂O and an unknown amount of CH₄ in the flask. Determine the concentration of CH₄ in the mixture. The equilibrium constant, K_c for the reaction at the given temperature is 3.90.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 35.

What is meant by conjugate acid-base pair ? Find the conjugate acid/base for the following species :
HNO₂,CN^–,HClO₄,OH^–,CO₃^2-,S^2-.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 36.

Which of the following are Lewis Acids ?
H₂O, BF₃, H⁺ and NH₄⁺

Solution.

BF₃, H⁺ and NH₄⁺ are Lewis acids because they can accept a lone pair of electrons.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 37.

What will be the conjugate bases for the Bronsted acids ? HF, H₂SO₄ and \({ HCO }_{ 3 }^{ – }\) ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 38.

Write the conjugate acids for the following Bronsted acids.
\({ NH }_{ 2 }^{ – }\), NH₃ and HCOO^–

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 39.

The species H₂O, HCO₃^–, HSO₄^– and NH₃ can act both as Bronsted acid and base. For each case, give the corresponding conjugate acid and base.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 40.

Classify the following species into Lewis acids and Lewis bases and show how these can act as Lewis acid/Lewis base ?
(a) OH^–
(b) F^–
(c) H⁺
(d) BCl₃

Solution.

(a) OH^– : OH^– is a Lewis base because it can donate lone pair of electrons.
(b) F^– : F^– is a Lewis base because it can donate lone pair of electrons.
(c) H⁺ : H⁺is a Lewis acid because it can accept lone pair of electrons.
(d) BCl₃ : is a Lewis acid because it is electron deficient and can accept a lone pair of electrons.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 41.

The concentration of hydrogen ions in a sample of soft drink is 3.8 × 10^-3 M. What is its pH value ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 42.

The pH of soft drink is 3.76. Calculate the concentration of hydrogen ions in it.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 43.

The ionisation constants of HF, HCOOH and HCN at 298 K are 6.8 x 10^-4, 1-8 × 10^-4 and 4.8 × 10^-9 respectively. Calculate the ionisation constant of the corresponding congugate bases.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 44.

The ionisation constant of phenol is 1.0 x 10^-10. What is the concentration of phenate ion in 0.05 M solution of phenol and pH of solution ? What will be the degree of ionisation if the solution is also 0.01 M in sodium phenate ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 45.

The first dissociation constant H₂S is 9.1 × 10^-8. Calculate the concentration of HS^– ions in its 0.1 M solution and how much will this concentration be affected if the solution is 0.1 M in HCl also. If the second dissociation constant of H₂S is 1.2 × 10^-13, calculate the concentration of S^2- ions under both the conditions.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 46.

The ionization constant of acetic acid is 1.74 × 10^-5. Calculate the degree of dissociation of acetic acid in 0.05 M solution. Calculate the concentration of acetate ions in solution and the pH of the solution.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 47.

It has been found that the pH of 0.01 M solution of organic acid is 4.15. Calculate the concentration of the anion, ionization constant of the acid and the pK_a.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 48.

Assuming complete dissociation, calculate the pH of the following solutions :
(a) 0.003 M HCl
(b) 0.005 M NaOH
(c) 0.002 M HBr
(d) 0.002 M KOH.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 49.

Calculate the pH of the following solutions :
(a) 2 g of TIOH dissolved in water to give 2 litre of solution.
(b) 0.3 g of Ca(OH)₂ dissolved in water to give 500 mL of solution.
(c) 0.3 g of NaOH dissolved in water to give 200 mL of solution.
(d) 1 mL of 13.6 M HCl diluted with water to give 1 litre of solution.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 50.

The degree of ionization of 0.1 M bromoacetic acid solution is 0.132. Calculate the pH of the solution and pK_a of bromoacetic acid.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 51.

The pH of 0-005 M codeine (C₁₈H₂₁NO₃) solution is 9.95. Calculate its ionizationconstant and pK_b.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 52.

What is the pH of 0.001 M aniline solution ? The ionization constant of aniline is 4.27 × 10^-10. Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjugate acid of aniline.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 53.

Calculate the degree of ionization of 0.05 M acetic acid if its pK_a value is 4.74. How is degree of dissociation affected when the solution contains (a) 0.01 M HCl (b) 0.1 M HCl ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 54.

The ionization constant of dimethylamine is 5.4 × 10^-4. Calculate the degree of ionization of its 0.02 M solution. What percentage of dimethylamine is ionized if the solution is also 0.01 M NaOH ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 55.

Calculate the hydrogen ion concentration in the following biological fluids whose pH values are as follows :
(a) Human muscles fluid 6.83
(b) Human stomach fluid 1.2.
(c) Human blood 7.38
(d) Human saliva 6.4

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 56.

The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8, 5.0, 4.2, 2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each case.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 57.

0.561 g KOH is dissolved in water to give 200 mL of solution at 298K. Calculate the concentration of potassium, hydrogen and hydroxyl ions. What is the pH of the solution ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 58.

The solubility of Sr(OH)₂ at 298 K is 19.23 g/L of solution. Calculate the concentrations of strontium and hydroxyl ions and the pH of the solution.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 59.

The ionisation constant of propionic acid is 1.32 × 10^-5. Calculate the degree of ionisation of acid in its 0.05 M solution and also its pH. What will be its degree of ionisation if the solution is 0.01 M in HCl also ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 60.

The pH of 0.1M solution of cyanic acid (HCNO) is 2.34. Calculate ionisation constant of the acid and also its degree of dissociation in the solution.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 61.

The ionisation constant of nitrous acid is 4.5 × 10^-4. Calculate the pH value of 0.04 M NaNO₂ solution and also its degree of hydrolysis.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 62.

A 0.02 M solution of pyridinium hydrochloride has pH = 3.44. Calculate the ionisation constant of pyridine.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 63.

Predict if the solutions of the following salts are neutral, acidic or basic :
NaCl, KBr, NaCN, NH₄NO₃, NaNO₂, and KF

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 64.

The ionisation constant of chloroacetic acid is 1.35 × 10^-3. What will be the pH of 0.1 M acid solution and of its 0.1 M sodium salt solution ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 65.

The ionic product of water at 310 K is 2.7 × 10^-14. What is the pH value of neutral water at this temperature ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 66.

Calculate the pH of the resultant mixtures:
(a) 10 mL. of 0.2 M Ca(OH)₂ + 25 mL of 0.1 M HCl
(b) 10 mL of 0.01 M H₂SO₄ + 10 mL of 0.01 M Ca(OH)₂
(c) 10 mL of 0.1 M H₂SO₄ + 10 mL of 0.1 M KOH.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 67.

Determine the solubilites of silver chromate, barium chromate and ferric hydroxide at 289 K from their solubility product constants. Determine also the molarities of the individual ions.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 68.

The solubility product constants of Ag₂CrO₄ and AgBr are 1.1 × 10^-12 and 5.0 × 10^-13 respectively. Calculate the ratio of the molarities of their saturated solutions.

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 69.

Equal volumes of 0.002 M solutions of sodium iodate and copper chlorate are mixed together. Will it lead to the precipitation of copper iodate ? (For copper iodate K_sp = 7.4 × 10^-8).

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 70.

The ionization constant of benzoic acid is 6.46 × 10^-5 and K_sp for silver benzoate is 2.5 × 10^-13. How many times is silver benzoate more soluble in a buffer of pH 3.19 compared to its solubility in pure water ?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 71.

What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide ? (For iron sulphide, K_sp = 6.3 × 10^-18).

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 72.

What is the minimum volume of water required to dissolve 1 g of calcium sulphate at 298 K. For calcium sulphate K_sp = 9.1 × 10^-6?

Solution.

NCERT Solutions for Class 11 Chemistry Chapter 7, Question 73.

The concentration of sulphide ion in 0.1 M HCl solution saturated with hydrogen sulphide is 1.0 × 10^-19 M. If 10 mL of this solution is added to 5 mL of 0.04 M solution of FeSO₄, MnCl₂, ZnCl₂ and CaCl₂, in which solutions precipitation will take place ?
Given K_sp for
FeS = 6.3 × 10^-18,
MnS = 2.5 × 10^-13,
ZnS = 1.6 × 10^-24 and
CdS = 8.0 × 10^-27.

Solution.

NCERT Class 11 Chemistry

Class 11 Chemistry Chapters | Chemistry Class 11 Chapter 7

Chapterwise NCERT Solutions for Class 11 Chemistry

NCERT Solutions For Class 11 Chemistry Chapter 1 Some Basic Concepts of Chemistry
NCERT Solutions For Class 11 Chemistry Chapter 2 Structure of The Atom
NCERT Solutions For Class 11 Chemistry Chapter 3 Classification of Elements and Periodicity in Properties
NCERT Solutions For Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure
NCERT Solutions For Class 11 Chemistry Chapter 5 States of Matter
NCERT Solutions For Class 11 Chemistry Chapter 6 Thermodynamics
NCERT Solutions For Class 11 Chemistry Chapter 7 Equilibrium
NCERT Solutions For Class 11 Chemistry Chapter 8 Redox Reactions
NCERT Solutions For Class 11 Chemistry Chapter 9 Hydrogen
NCERT Solutions For Class 11 Chemistry Chapter 10 The sBlock Elements
NCERT Solutions For Class 11 Chemistry Chapter 11 The pBlock Elements
NCERT Solutions For Class 11 Chemistry Chapter 12 Organic Chemistry: Some Basic Principles and Techniques
NCERT Solutions For Class 11 Chemistry Chapter 13 Hydrocarbons
NCERT Solutions For Class 11 Chemistry Chapter 14 Environmental Chemistry

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