NCERT Solutions | Class 12 Chemistry Chapter 3 | Electro chemistry

CBSE Solutions | Chemistry Class 12
Check the below NCERT Solutions for Class 12 Chemistry Chapter 3 Electro chemistry Pdf free download. NCERT Solutions Class 12 Chemistry were prepared based on the latest exam pattern. We have Provided Electro chemistry Class 12 Chemistry NCERT Solutions to help students understand the concept very well.
NCERT | Class 12 Chemistry
Book: | National Council of Educational Research and Training (NCERT) |
---|---|
Board: | Central Board of Secondary Education (CBSE) |
Class: | 12th |
Subject: | Chemistry |
Chapter: | 3 |
Chapters Name: | Electro chemistry |
Medium: | English |
Electro chemistry | Class 12 Chemistry | NCERT Books Solutions
NCERT Exercises
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 1.
Solution.
Set up an electrochemical cell consisting of MglMgSO4(1 M) as one electrode by dipping a magnesium wire in 1 M MgSO4 solution and standard hydrogen electrode Pt, H2 (1 atm) | H+(1 M) as the second electrode. Measure the EMF of the cell and also note the direction of deflection in the voltmeter. The direction of deflection shows that the electrons flow from magnesium electrode to hydrogen electrode, i.e., oxidation takes place on magnesium electrode and reduction on hydrogen electrode.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 2.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 3.
Solution.
Oxidation of ferrous ions means :
Only those substances can oxidise Fe2+ to Fe3+ which are stronger oxidising agents and have positive reduction potentials greater than 0.77 V so that EMF of the cell reaction is positive. This is for elements lying below Fe3+/Fe2+ in the electrochemical series, for example, Br2, Cl2 and F2.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 4.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 5.
Ni(S) + 2Ag+ (0.002 M) → Ni2+(0.160 M) + 2Ag(S)
Given that E°cell = 1.05 V
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 6.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 7.
Solution.
Conductivity of solution decreases with dilution because number of ions per unit volume decreases.NCERT Solutions for Class 12 Chemistry Chapter 3, Question 8.
Solution.
Water is a weak electrolyte. Its A°m value can be determined with the help of Kohlrausch’s law.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 9.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 10.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 11.
Solution.
Ca, Na, K, Al are extracted electrolytically.NCERT Solutions for Class 12 Chemistry Chapter 3, Question 12.
Cr2O2-7 + 14H+ + 6e– → 2Cr3+ + 7H2O,
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2 O2-7?
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 13.
Solution.
Chemical reactions while recharging :2PbSO4 + 2H2O → PbO2 + Pb + 2H2SO4
Electricity is passed through the electrolyte PbSO4 which is converted into PbO2 and Pb.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 14.
Solution.
CH4 and CO can be used in fuel cell instead of hydrogen.NCERT Solutions for Class 12 Chemistry Chapter 3, Question 15.
Solution.
The following reactions take place at the surface of iron metal which acts as an electrochemical cell.
The water layer present on the surface of iron dissolves acidic oxides of air like C02 to form acids which dissociate to give H+ ions. Fe starts losing electrons in presence of H+ ions.
H2O + CO2 → H2CO3 \(\rightleftharpoons \) 2H+ + C032-
NCERT Exercises
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 1.
Al, Cu, Fe, Mg and Zn.
Solution.
Mg, Al, Zn, Fe, CuNCERT Solutions for Class 12 Chemistry Chapter 3, Question 2.
K+/ K = – 2.93 V, Ag+/ Ag = 0.80 V, Hg2+/ Hg = 0.79 V, Mg2+/ Mg = -2.37 V, Cr3+/ Cr = – 0.74 V
Arrange these metals in their increasing order of reducing power.
Solution.
Higher the oxidation potential, more easily it is oxidized and hence greater is the reducing power. Thus, increasing order of reducing power will beAg < Hg < Cr < Mg < K.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 3.
- Which of the electrode is negatively charged?
- The carriers of the current i n the cell.
- Individual reaction at each electrode.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 4.

Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 5.

Solution.




NCERT Solutions for Class 12 Chemistry Chapter 3, Question 6.

Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 7.
Solution.
The reciprocal of resistivity is known as specific conductance or simply conductivity. It is denoted by K (kappa). Thus, if K is the specific conductance and G is the conductance of the solution, then
Now, if I = 1 cm and A = lsq.cm, then K = G.
Hence, conductivity of a solution is defined as the conductance of a solution of 1 cm length and having 1 sq. cm as the area of cross¬section. Alternatively, it may be defined as conductance of one centimetre cube of the solution of the electrolyte.
Molar conductivity of a solution at a dilution V is the conductance of all the ions produced from 1 mole of the electrolyte dissolved in V cm3 of the solution when the electrodes are one cm apart and the area of the electrodes is so large that the whole of the solution is contained between them. It is represented by ∆m.
Variation of conductivity and molar conductivity with concentration: Conductivity always decreases with decrease in concentration, for both weak and strong electrolytes. This is because the number of ions per unit volume that carry the current in a solution decreases on dilution.
Molar conductivity increases with decrease in concentration. This is because that total volume, V, of solution containing one mole of electrolyte also increases. It has been found that decrease in K on dilution of a solution is more than compensated by increase in its volume.
NCERT Solutions for Class 12 Chemistry Chapter 3, Question 8.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 9.
Solution.
Cell constant = K × R = 0.146 × 10-3 × 1500 = 0.219 cm-1NCERT Solutions for Class 12 Chemistry Chapter 3, Question 10.
Concentration/M 0.001 0.010 0.020 0.050 0.100
102 × K/S m-1 1.237 11.85 23.15 55.53 106.74
Calculate ∆m for all concentrations and draw a plot between ∆m and c1/2. Find the value of ∆°m
Solution.



NCERT Solutions for Class 12 Chemistry Chapter 3, Question 11.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 12.
- 1 mol of Al3+to Al ?
- 1 mol of Cu2+ to Cu ?
- 1 mol of MnO4– to Mn2+ ?
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 13.
- 20.0 g of Ca from molten CaCl2?
- 40.0 g of Al from molten Al2O3?
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 14.
- 1 mol of H2O to O2?
- 1 mol of FeO to Fe2O3?
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 15.
(At. mass of Ni = 58.7)
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 16.
(At. wt. of Ag = 108, Cu = 63.5, Zn = 65.3)
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 3, Question 17.

Solution.

NCERT Solutions for Class 12 Chemistry Chapter 3, Question 18.
- An aqueous solution of AgNO3 with silver electrodes.
- An aqueous solution of AgNO3 with platinum electrodes.
- A dilute solution of H2SO4 with platinum electrodes.
- An aqueous solution of CuCI2 with platinum electrodes.
Solution.


NCERT Class 12 Chemistry
Class 12 Chemistry Chapters | Chemistry Class 12 Chapter 3
Chapterwise NCERT Solutions for Class 12 Chemistry
-
NCERT Solutions For Class 12 Chemistry Chapter 1 The Solid State
NCERT Solutions For Class 12 Chemistry Chapter 2 Solutions
NCERT Solutions For Class 12 Chemistry Chapter 3 Electro chemistry
NCERT Solutions For Class 12 Chemistry Chapter 4 Chemical Kinetics
NCERT Solutions For Class 12 Chemistry Chapter 5 Surface Chemistry
NCERT Solutions For Class 12 Chemistry Chapter 6 General Principles and Processes of Isolation of Elements
NCERT Solutions For Class 12 Chemistry Chapter 7 The p Block Elements
NCERT Solutions For Class 12 Chemistry Chapter 8 The d and f Block Elements
NCERT Solutions For Class 12 Chemistry Chapter 9 Coordination Compounds
NCERT Solutions For Class 12 Chemistry Chapter 10 Haloalkanes and Haloarenes
NCERT Solutions For Class 12 Chemistry Chapter 11 Alcohols Phenols and Ethers
NCERT Solutions For Class 12 Chemistry Chapter 12 Aldehydes Ketones and Carboxylic Acids
NCERT Solutions For Class 12 Chemistry Chapter 13 Amines
NCERT Solutions For Class 12 Chemistry Chapter 14 Biomolecules
NCERT Solutions For Class 12 Chemistry Chapter 15 Polymers
NCERT Solutions For Class 12 Chemistry Chapter 16 Chemistry in Everyday Life
NCERT Solutions for Class 12 All Subjects | NCERT Solutions for Class 10 All Subjects |
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