NCERT Solutions | Class 12 Chemistry Chapter 4 | Chemical Kinetics

CBSE Solutions | Chemistry Class 12
Check the below NCERT Solutions for Class 12 Chemistry Chapter 4 Chemical Kinetics Pdf free download. NCERT Solutions Class 12 Chemistry were prepared based on the latest exam pattern. We have Provided Chemical Kinetics Class 12 Chemistry NCERT Solutions to help students understand the concept very well.
NCERT | Class 12 Chemistry
Book: | National Council of Educational Research and Training (NCERT) |
---|---|
Board: | Central Board of Secondary Education (CBSE) |
Class: | 12th |
Subject: | Chemistry |
Chapter: | 4 |
Chapters Name: | Chemical Kinetics |
Medium: | English |
Chemical Kinetics | Class 12 Chemistry | NCERT Books Solutions
NCERT Exercises
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 1.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 2.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 3.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 4.
Solution.
The reaction, X → Y, follows second order kinetics hence the rate law equation will beRate = kC2, where C = [X]
If concentration of X increases three times, now, [X] = 3C mol L-1
∴ Rate = k(3C)2 = 9kC2
Thus the rate of reaction will become 9 times. Hence, the rate of formation of Y will increase 9 times.
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 5.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 6.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 7.
Solution.
It has been found that for a chemical reaction, with rise in temperature by 10°, the rate constant is nearly doubled.The temperature dependence of the rate of a chemical reaction can be accurately explained by Arrhenius equation.
K = Ae-Ea/RT
Where A is the Arrhenius factor or the frequency factor. It is also called pre exponential factor. It is a constant specific to a particular reaction. R is gas constant and Ea is activation energy measured in joules/mole (J mol-1).
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 8.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 9.
Solution.
Fraction of molecules having energy equal to or greater than activation energy is given as
NCERT Exercises
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 1.

Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 2.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 3.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 4.
Rate = k[CH3OCH3]3/2
The rate of reaction is followed by increase in pressure in closed vessel, so the rate can also be expressed in terms of the partial pressure of dimethyl ether, i.e.,
Rate = K(pCH3OCH3)3/2
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constants ?
Solution.
In terms of pressure,Units of rate = bar min-1

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 5.
Solution.
Following are the factors on which rate of reaction depends.(i) Nature of the reactant : Rate of reaction depends on nature of reactant.
Example : Reactions of ionic compounds are faster than that of covalent compounds.
(ii) State of reactants : Solid reactions are slow, reactions of liquids are fast whereas that of gases are very fast.
(iii) Temperature : Rate of reaction largely depends on temperature. It has been observed that every 10°C rise in temperature increases rate of reaction by 2-3 times.
\(\frac { { r }_{ t }+10 }{ { r }_{ t } } \) = 2 – 3 . This ratio is called temperature coefficient.
There are two reasons for increasing rate of reaction with increasing temperature.
(a) Increase in temperature increases average kinetic energy of reactant molecules. Hence, rate of collision increases.
(b) With increase in temperature number of molecules having threshold energy also increases i.e. number of active molecules increases. As a result, number of effective collisions increases. Hence, rate of reaction increases.
(iv) Concentration : Rate of reaction also depends on concentration of reactants.
Rate = k × C”, where n = order of reaction, C = concentration of reactant.
(v) Presence of catalyst : Rate of reaction also depends on presence of catalyst. Catalyst increases rate of reaction by any of the following ways:
(a) Increasing surface area of reaction.
(b) Adsorbing the reactants on its surface and thus increasing chance of collision.
(c) By forming unstable intermediate with the substrate.
(d) By providing alternate path of lower activation energy.
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 6.
- doubled
- reduced to half ?
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 7.
Solution.
The rate constant increases with increase in temperature and becomes almost double for every 10° increase in temperature. Swedish chemist, Arrhenius derived a quantitative relation between rate of reaction and temperature. According to Arrhenius,
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 8.

- Calculate the average rate of reaction between the time interval 30 to 60 seconds.
- Calculate the pseudo first order rate constant for the hydrolysis of ester.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 9.
- Write the differential rate equation.
- How is the rate affected on increasing the concentration of 6 three times?
- How is the rate affected when the concentrations of both A and B are doubled?
Solution.
(i) Reaction is first order in A and second order in B, hence differential rate equation is
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 10.

What is the order of the reaction with respect to A and B ?
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 11.
2 A + B → C + D

Determine the rate law and the rate constant for the reaction.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 12.

Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 13.
- 200 s-1
- 2 min-1
- 4 year-1
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 14.
Solution.
Radioactive decay follows first order kinetics. Therefore,
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 15.
[2N2O5 → 4NO2 + O2]
in gas phase at 318K are given below :

- Plot [N2O5] against t.
- Find the half-life period for the reaction.
- Draw a graph between log [N2O5] and t.
- What is the rate law?
- Calculate the rate constant.
- Calculate the half-life period from k and compare it with (ii).
Solution.




NCERT Solutions for Class 12 Chemistry Chapter 4, Question 16.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 17.
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 18.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 19.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 20.

Calculate the rate constant
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 21.

Calculate the rate of the reaction when total pressure is 0.65 atm.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 22.

Draw a graph between In k and 1/7 and calculate the value of A and Ea. Predict the rate constant at 30°C and 50°C.
Solution.
The values of rate constants for the decomposition of N2O5 at various temperatures are given below :


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 23.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 24.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 25.
Solution.
Sucrose decomposes according to first order rate law, hence
NCERT Solutions for Class 12 Chemistry Chapter 4, Question 26.

Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 27.
log k = 14.34 – 1.25 × 104 K/T
Calculate Ea for this reaction and at what temperature will its half-period be 256 minutes?
Solution.


NCERT Solutions for Class 12 Chemistry Chapter 4, Question 28.
Solution.

NCERT Solutions for Class 12 Chemistry Chapter 4, Question 29.
Solution.



NCERT Solutions for Class 12 Chemistry Chapter 4, Question 30.
Solution.

NCERT Class 12 Chemistry
Class 12 Chemistry Chapters | Chemistry Class 12 Chapter 4
Chapterwise NCERT Solutions for Class 12 Chemistry
-
NCERT Solutions For Class 12 Chemistry Chapter 1 The Solid State
NCERT Solutions For Class 12 Chemistry Chapter 2 Solutions
NCERT Solutions For Class 12 Chemistry Chapter 3 Electro chemistry
NCERT Solutions For Class 12 Chemistry Chapter 4 Chemical Kinetics
NCERT Solutions For Class 12 Chemistry Chapter 5 Surface Chemistry
NCERT Solutions For Class 12 Chemistry Chapter 6 General Principles and Processes of Isolation of Elements
NCERT Solutions For Class 12 Chemistry Chapter 7 The p Block Elements
NCERT Solutions For Class 12 Chemistry Chapter 8 The d and f Block Elements
NCERT Solutions For Class 12 Chemistry Chapter 9 Coordination Compounds
NCERT Solutions For Class 12 Chemistry Chapter 10 Haloalkanes and Haloarenes
NCERT Solutions For Class 12 Chemistry Chapter 11 Alcohols Phenols and Ethers
NCERT Solutions For Class 12 Chemistry Chapter 12 Aldehydes Ketones and Carboxylic Acids
NCERT Solutions For Class 12 Chemistry Chapter 13 Amines
NCERT Solutions For Class 12 Chemistry Chapter 14 Biomolecules
NCERT Solutions For Class 12 Chemistry Chapter 15 Polymers
NCERT Solutions For Class 12 Chemistry Chapter 16 Chemistry in Everyday Life
NCERT Solutions for Class 12 All Subjects | NCERT Solutions for Class 10 All Subjects |
NCERT Solutions for Class 11 All Subjects | NCERT Solutions for Class 9 All Subjects |
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