NCERT Solutions | Class 7 Maths Chapter 13

NCERT Solutions | Class 7 Maths Chapter 13 | Exponents and Powers 

CBSE Solutions | Maths Class 7

Check the below NCERT Solutions for Class 7 Maths Chapter 13 Exponents and Powers Pdf free download. NCERT Solutions Class 7 Maths  were prepared based on the latest exam pattern. We have Provided Exponents and Powers Class 7 Maths NCERT Solutions to help students understand the concept very well.

NCERT | Class 7 Maths

NCERT Solutions Class 7 Maths

Book:	National Council of Educational Research and Training (NCERT)
Board:	Central Board of Secondary Education (CBSE)
Class:	7th
Subject:	Maths
Chapter:	13
Chapters Name:	Exponents and Powers
Medium:	English

Exponents and Powers | Class 7 Maths | NCERT Books Solutions

You can refer to MCQ Questions for Class 7 Maths Chapter 13 Exponents and Powers to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.

NCERT Solutions for Class 7 Chapter 13 Question 1.

Find the value of:

(i) 2⁶

Solution:

2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64

(ii) 9³

Solution:

9² = 9 × 9 × 9 = 729

(iii) 11²

Solution:

11² = 11 × 11 = 121

(iv) 5⁴

Solution:

5⁴ = 5 × 5 × 5 × 5 = 625

NCERT Solutions for Class 7 Chapter 13 Question 2.

Express the following in exponential form :

(i) 6 × 6 × 6 × 6

Solution:

6 × 6 × 6 × 6 = 6⁴

(ii) t x t

Solution:

t × t = t²

(iii) b × b × b × b

Solution:

b × b × b × b = b⁴

(iv) 5 × 5 × 7 × 7 × 7

Solution:

5 × 5 × 7 × 7 × 7 = 5² × 7³

(v) 2 × 2 × a × a

Solution:

2 × 2 × a × a = 2² × a²

(vi) a × a × a × c × c × c × c × d

Solution:

a × a × a × c × c × c × c d = a³ × c⁴ × d

NCERT Solutions for Class 7 Chapter 13 Question 3.

Express each of the following numbers using the exponential notation:

(i) 512

Solution:

We have

(ii) 343

Solution:

We have

(iii) 729

Solution:

We have

(vi) 3125

Solution:

We have

NCERT Solutions for Class 7 Chapter 13 Question 4.

Identify the greater number, wherever possible, in each of the following?

(i) 4³ or 3⁴

Solution:

(ii) 5³ or 3⁵

Solution:

(iii) 2⁸ or 8²

Solution:

(iv) 100² or 2¹⁰⁰

Solution:

(v) 2¹⁰ or 10²

Solution:

NCERT Solutions for Class 7 Chapter 13 Question 5.

Express each of the following as a product of powers of their prime factors:

(i) 648

Solution:

To determine the prime factorization of 648, we use the division method, as shown below:

(ii) 405

Solution:

We use the division method as shown under:

(iii) 540

Solution:

We use the division method as shown under:

(iv) 3600

Solution:

We use the division method as shown under:

NCERT Solutions for Class 7 Chapter 13 Question 6.

Simplify:

(i) 2 × 10³

Solution:

2 × 10³ = 2 × 1000 = 2000

(ii) 7² x 2²

Solution:

7² × 2² = (7 × 2)² = (14)³ = 14 × 14 = 196

(iii) 2³ × 5

Solution:

2³ × 5 = 2 × 2 × 2 × 5
= 8 × 5 = 40

(iv) 3 × 4⁴

Solution:

3 × 4⁴ = 3 × 4 × 4 × 4 × 4
= 3 × 256 = 768

(v) 0 × 10²

Solution:

0 × 10² = 0

(vi) 5² × 3³

Solution:

5² × 3³ = 5 × 5 × 3 × 3 × 3 = 25 × 27 = 675

(vii) 24 × 32

Solution:

2⁴ × 3² = 2 × 2 × 2 × 2 × 3 × 3 = 16 × 9 = 144

(viii) 3² × 10⁴

Solution:

3² × 10⁴ = 3 × 3 × 10 × 10 × 10 × 10 = 9 × 10000 = 90000

NCERT Solutions for Class 7 Chapter 13 Question 7.

Simplify:

(i) (-4)³

Solution:

(- 4)³ = (- 4) × (- 4) × (- 4) = – 64

(ii) (-3) × (-2)³

Solution:

(-3) × (-2)³ = (-3) × (- 2) × (- 2) × (- 2) = (- 3) × (- 8) = 24

(iii) (- 3)² × (- 5)2

Solution:

(- 3)² × (- 5)² = (- 3) × (- 3) × (- 5) × (- 5) = 9 × 25 = 225

(iv) (-2)³ × (-10)²

Solution:

(-2)³ × (-10)³ = (-2) × (-2) × (-2) x (-10) × (-10) × (-10) = (-8) × (-1000) = 8000

NCERT Solutions for Class 7 Chapter 13 Question 8.

Compare the following numbers:

(i) 2.7 × 10¹² ; 1.5 × 10⁸

Solution:

We have,
2.7 × 10¹² = 2.7 × 10 × 10¹¹
= 27 × 10¹¹, contains 13 digits and 1.5 × 10⁸ = 1.5 × 10 × 10⁷
= 15 × 10⁷ contains 9 digits
Clearly, 2.7 × 10¹² > 1.5 × 10⁸

(ii) 4 × 10¹⁴; 3 × 10¹⁷

Solution:

We have, 4 × 10¹⁴, contains 15 digits and, 3 × 10¹⁷, contains 18 digits 4 × 10¹⁴ < 3 × 10¹⁷