NCERT Solutions  Class 7 Maths Chapter 6  The Triangles and its Properties
CBSE Solutions  Maths Class 7
Check the below NCERT Solutions for Class 7 Maths Chapter 6 The Triangles and its Properties Pdf free download. NCERT Solutions Class 7 Maths were prepared based on the latest exam pattern. We have Provided The Triangles and its Properties Class 7 Maths NCERT Solutions to help students understand the concept very well.
NCERT  Class 7 Maths
Book:  National Council of Educational Research and Training (NCERT) 

Board:  Central Board of Secondary Education (CBSE) 
Class:  7th 
Subject:  Maths 
Chapter:  6 
Chapters Name:  The Triangles and its Properties 
Medium:  English 
The Triangles and its Properties  Class 7 Maths  NCERT Books Solutions
You can refer to MCQ Questions for Class 7 Maths Chapter 6 The Triangles and its Properties to revise the concepts in the syllabus effectively and improve your chances of securing high marks in your board exams.
NCERT Solutions for Class 7 Maths Chapte 6 The Triangle and its Properties Exercise 6.1
Ex 6.1 Class 7 Maths Question 1.
Solution:
Ex 6.1 Class 7 Maths Question 2.
Draw rough sketches for the following :(a) In ∆ABC, BE is a median.
(b) in ∆PQR, PQ and PR are altitudes of the triangle.
(c) In ∆XYZ, YL is an altitude In the exterior of the triangle.
Solution:
(a) Rough sketch of median BE of ∆ABC is as shown.(b) Rough sketch of altitudes PQ and PR of ∆PQR is as shown.
(c) Rough sketch of an exterior altitude YL of ∆XYZ is as shown.
Ex 6.1 Class 7 Maths Question 3.
Verify by drawing a diagram if ‘the median and altitude of an isosceles triangle can be same.Solution:
Draw a line segment BC. By paper folding, locate the perpendicular bisector of BC. The folded crease meets BC at D, its midpoint.
Take any point A on this perpendicular bisector. Join AB and AC. The triangle thus obtained is an isosceles ∆ABC in which AB = AC.
Since D is the midpoint of BC, so AD is its median. Also, AD is the perpendicular bisector of BC. So, AD is the altitude of ∆ABC.
Thus, it is verified that the median and altitude of an isosceles triangle are the same.
NCERT Solutions for Class 7 Maths Chapte 6 The Triangle and its Properties Exercise 6.2
Ex 6.2 Class 7 Maths Question 1.
Find the value of the unknown exterior angle x in the following diagrams :Solution:
Since, in a triangle an exterior angle is equal to the sum of the two interior opposite angles, therefore, x = 50°+ 70° = 120°
 x = 65°+ 45° = 110°
 x = 30°+ 40°= 70°
 x = 60° + 60° = 120c
 x = 50° + 50° = 100c
 x = 30°+ 60° = 90°
Ex 6.2 Class 7 Maths Question 2.
Find the value of the unknown interior angle x in the following figures :Solution:
We know that in a triangle, an exterior angle is equal to the sum of the two interior opposite angles. Therefore,NCERT Solutions for Class 7 Maths Chapte 6 The Triangle and its Properties Exercise 6.3
Ex 6.3 Class 7 Maths Question 1.
Find the value of the unknown x in the following diagrams :Solution:
Ex 6.3 Class 7 Maths Question 2.
Find the values of the unknowns x and y in the following diagrams :Solution:
NCERT Solutions for Class 7 Maths Chapte 6 The Triangle and its Properties Exercise 6.4
Ex 6.4 Class 7 Maths Question 1.
Is it possible to have a triangle with the following sides?(i) 2 cm, 3 cm, 5 cm
(ii) 3 cm, 6 cm, 7 cm
(iii) 6 cm, 3 cm, 2 cm
Solution:
(i) Since, 2 + 3 > 5So the given side lengths cannot form a triangle.
(ii) We have, 3 + 6 > 7, 3 + 7 > 6 and 6 + 7 > 3
i. e., the sum of any two sides is greater than the third side.
So, these side lengths form a triangle.
(iii) We have, 6 + 3 > 2, 3 + 2 \(\ngtr \) 6
So, the given side lengths cannot form a triangle.
Ex 6.4 Class 7 Maths Question 2.
Take any point O in the interior of a triangle PQR. Is(i) OP + OQ > PQ?
(ii) OQ + OR > QR ?
(iii) OR + OP > RP ?
Solution:
(i) Yes, OP + OQ > PQ because on joining OP and OQ, we get a ∆OPQ and in a triangle, sum of the lengths of any two sides is always greater than the third side.(ii) Yes, OQ + OR > QR, because on joining OQ and
OR, we get a ∆OQR and in a triangle, sum of the length of any two sides is always greater than the third side.
(iii) Yes, OR + OP > RP, because on joining OR and OP, we get a ∆OPR and in a triangle, sum of the lengths of any two sides is always greater than the third side.
Ex 6.4 Class 7 Maths Question 3.
AM is median of a triangle ABC. Is AB + BC + CA > 2AM?(Consider the sides of triangles ∆ABM and ∆AMC.)
Solution:
Using triangle inequality property in triangles ABM and AMC, we haveAB + BM > AM …(1) and, AC + MC > AM …(2)
Adding (1) and (2) on both sides, we get
AB + (BM + MC) + AC > AM + AM
⇒ AB + BC + AC > 2AM
Ex 6.4 Class 7 Maths Question 4.
ABCD is a quadrilateral. Is AB + BC + CD + DA > AC + BD?Solution:
Ex 6.4 Class 7 Maths Question 5.
ABCD is a quadrilateral. Is AB + BC + CD + DA < 2(AC + BD)?Solution:
Let ABCD be a quadrilateral and its diagonals AC and BD intersect at O. Using triangle inequality property, we haveIn ∆OAB
OA + OB > AB ……(1)
Ex 6.4 Class 7 Maths Question 6.
The lengths of two sides of a triangle are 12 cm and 15 cm. Between what two measures should the length of the third side fall?Solution:
Let x cm be the length of the third side.Thus, 12 + 15 > x, x + 12 > 15 and x + 15 > 12
⇒ 27 > x, x > 3 and x > 3
The numbers between 3 and 27 satisfy these.
∴ The length of the third side could be any length between 3 cm and 27 cm.
NCERT Solutions for Class 7 Maths Chapte 6 The Triangle and its Properties Exercise 6.5
Ex 6.5 Class 7 Maths Question 1.
PQR is a triangle, rightangled at P. If PQ = 10 cm and PR? = 24 cm, find QR.Solution:
Ex 6.5 Class 7 Maths Question 2.
ABC is a triangle rightangled atC. If AB = 25 cm and AC = 7cm, find BC.Solution:
Ex 6.5 Class 7 Maths Question 3.
A 15 m long ladder reached a window 12 m high from the ground on placing it against a wall at a distance a. Find the distance of the foot of the ladder from the wall.Solution:
Hence, the distance of the foot of the ladder from the wall is 9 m.
Ex 6.5 Class 7 Maths Question 4.
Which of the following can be the sides of a right triangle?(i) 2.5 em, 6.5 cm, 6 cm.
(ii) 2 cm, 2 cm, 5 cm.
(iii) 1.5 cm, 2 cm, 2.5 cm.
In the case of rightangled triangles, identify the right angles.
Solution:
Thus, the given sides form a righttriangle and the rightangle is opposite to the side of length 2.5 cm.
Ex 6.5 Class 7 Maths Question 5.
A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.Solution:
Let ACB be the tree before it broke at the point C. and let its top A touch the ground at A^{‘} after it broke. Then, ∆A^{‘}BC is a right triangle, rightangled at B such that A’ B = 12 m, BC = 5 m. By Pythagoras theorem, we have
Ex 6.5 Class 7 Maths Question 6.
Angles Q and ii of a APQR are 25° and 65°. Write which of the following is true :(i) PQ^{2} + QR^{2} = RP^{2}
(ii) PQ^{2} + RP^{2} = QR^{2}
(iii) RP^{2} + QR^{2} = PQ^{2 }
Solution:
Ex 6.5 Class 7 Maths Question 7.
Find the perimeter of the rectangle whose length is 40 cm and a diagonal is 41 cm.Solution:
Let ABCD be a rectangle such that AB = 40 m and AC = 41 m.In rightangled ∆ABC, rightangled at B, by Pythagoras theorem, we have BC^{2} = AC^{2} – AB^{2 }
Ex 6.5 Class 7 Maths Question 8.
The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.Solution:
Let ABCD be the rhombus such that AC = 30 cm and BD = 16 cm.We know that the diagonals of a rhombus bisect each other at right angles.
NCERT Class 7 Maths
Class 7 Maths Chapters  Maths Class 7 Chapter 6
NCERT Solutions for Class 7 Maths
NCERT Solutions of Maths Class 7 Chapterwise
Chapterwise NCERT Solutions for Class 7 Maths

NCERT Solutions For Class 7 Maths Chapter 1 Integers
NCERT Solutions For Class 7 Maths Chapter 2 Fractions and Decimals
NCERT Solutions For Class 7 Maths Chapter 3 Data Handling
NCERT Solutions For Class 7 Maths Chapter 4 Simple Equations
NCERT Solutions For Class 7 Maths Chapter 5 Lines and Angles
NCERT Solutions For Class 7 Maths Chapter 6 The Triangles and its Properties
NCERT Solutions For Class 7 Maths Chapter 7 Congruence of Triangles
NCERT Solutions For Class 7 Maths Chapter 8 Comparing Quantities
NCERT Solutions For Class 7 Maths Chapter 9 Rational Numbers
NCERT Solutions For Class 7 Maths Chapter 10 Practical Geometry
NCERT Solutions For Class 7 Maths Chapter 11 Perimeter and Area
NCERT Solutions For Class 7 Maths Chapter 12 Algebraic Expressions
NCERT Solutions For Class 7 Maths Chapter 13 Exponents and Powers
NCERT Solutions For Class 7 Maths Chapter 14 Symmetry
NCERT Solutions For Class 7 Maths Chapter 15 Visualising Solid Shapes
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