NCERT Solutions | Class 7 Maths Chapter 7 | Congruence of Triangles

CBSE Solutions | Maths Class 7
Check the below NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Pdf free download. NCERT Solutions Class 7 Maths were prepared based on the latest exam pattern. We have Provided Congruence of Triangles Class 7 Maths NCERT Solutions to help students understand the concept very well.
NCERT | Class 7 Maths
Book: | National Council of Educational Research and Training (NCERT) |
---|---|
Board: | Central Board of Secondary Education (CBSE) |
Class: | 7th |
Subject: | Maths |
Chapter: | 7 |
Chapters Name: | Congruence of Triangles |
Medium: | English |
Congruence of Triangles | Class 7 Maths | NCERT Books Solutions
NCERT Solutions for Class 7 Maths Chapte 7 Congruence of Triangles Exercise 7.1
Ex 7.1 Class 7 Maths Question 1.
Complete the following statements:(a) Two line segments are congruent if
(b) Among two congruent angles, one has a measure of 70°; the measure of the other angle is
(c) When we write ∠A = ∠B, we actually mean
Solution:
(a) Two line segments are congruent if they have the same length.
(b) Among two congruent angles, one has a measure of 70° the measure of the other angle is 70°.
(c) When we write ∠A = ∠B, we actually mean m ∠A = m ∠B.
Ex 7.1 Class 7 Maths Question 2.
Give any two real-life examples for congruent shapes.Solution:
Two one-rupee coins, two ten-rupee notes.Ex 7.1 Class 7 Maths Question 3.
If ∆ABC = FED under the correspondence ABC ↔ FED, write all the corresponding congruent parts of the triangles.Solution:
∆ABC = ∆FED means that ∆ABC superposes on ∆FED exactly such that the vertices of ∆ABC fall on the vertices of ∆FED in the following order A ↔ F, B ↔ E and C ↔ D.
Ex 7.1 Class 7 Maths Question 4.
If ∆DEF = BCA, write the part(s) of ∆BCA that correspond to
Solution:

NCERT Solutions for Class 7 Maths Chapte 7 Congruence of Triangles Exercise 7.2
Ex 7.2 Class 7 Maths Question 1.
Which congruence criterion do you use in the following ?
Solution:


Ex 7.2 Class 7 Maths Question 2.
You want to show that ∆ART = ∆PEN.
(a) If you have to use SSS criterion, then you need to
- AR =
- RT =
- AT =
(b) If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have
- RT = and,
- PN =
(c) If it is given that AT = PN and you are to use ASA criterion, you need to have
- ?
- ?
Solution:
(a) In order to show that ∆ART = ∆PEN using SSS criterion, we need to show that
- AR = PE
- RT = EN
- AT = PN
(b) If m∠T = m∠N and to use SAS criterion, we need to show that
- RT = EN and
- PN = AT
(c) If AT = PN and to use ASA criterion, we need to show that
- ∠RAT = ∠EPN and
- ∠ATR = ∠PNE
Ex 7.2 Class 7 Maths Question 3.

Solution:

Ex 7.2 Class 7 Maths Question 4.
In ∆ABC, ∠A = 30°, ∠B = 40° and ∠C = 110°In ∆PQR, ∠P = 30°, ∠Q = 40° and ∠R = 110°.
A student says that ∆ABC = ∆PQR by AAA congruence criterion. Is he justified? Why or why not?
Solution:
In two triangles, if the three angles of one triangle are respectively equal to the three angles of the other, then the triangles are not necessarily congruent.
Ex 7.2 Class 7 Maths Question 5.
In the figure, the two triangles are congruent The corresponding parts are ∆ RAT = ?
Solution:

Ex 7.2 Class 7 Maths Question 6.
Complete the congruence statement :
Solution:


Ex 7.2 Class 7 Maths Question 7.
In a squared sheet, draw two triangles of equal areas such that(i) the triangles are congruent.
(ii) the triangles are not congruent.
What can you say about their perimeters?
Solution:


Ex 7.2 Class 7 Maths Question 8.
Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.Solution:
In some special cases (which depend on the lengths of the sides and the size of the angle involved),SSA is enough to show congruence. However, it is not always enough. Consider the following triangles :
Here side AB is congruent to side DE (S) side AC is congruent to side DF(S) angle C is congruent to angle F(A)
But the triangles are not congruent, as we can see.
What happens is this : If we draw a vertical line through point A in the first triangle, we can sort of “flip” side AB around this line to get the second triangle. If we were to lay one triangle on top of the other and draw the vertical line, this how it would look.
Clearly, side DE is just side AB flipped around the line. So, we have not changed the length of the side, and the other side AC (or DF) is unchanged, as is angle C (or F). So, these two triangles that have the same SSA information, but they are not congruent.
Ex 7.2 Class 7 Maths Question 9.
If ∆ABC and ∆PQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?
Solution:
In order prove that ∆ABC ≅ ∆PQR, the additional pair of corresponding parts are named as BC = QR.Criterion used is ASA rule of congruence
Ex 7.2 Class 7 Maths Question 10.
Explain, why ∆ABC ≅ ∆FED
Solution:

NCERT Class 7 Maths
Class 7 Maths Chapters | Maths Class 7 Chapter 7
NCERT Solutions for Class 7 Maths
NCERT Solutions of Maths Class 7 Chapter-wise
Chapter-wise NCERT Solutions for Class 7 Maths
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NCERT Solutions For Class 7 Maths Chapter 1 Integers
NCERT Solutions For Class 7 Maths Chapter 2 Fractions and Decimals
NCERT Solutions For Class 7 Maths Chapter 3 Data Handling
NCERT Solutions For Class 7 Maths Chapter 4 Simple Equations
NCERT Solutions For Class 7 Maths Chapter 5 Lines and Angles
NCERT Solutions For Class 7 Maths Chapter 6 The Triangles and its Properties
NCERT Solutions For Class 7 Maths Chapter 7 Congruence of Triangles
NCERT Solutions For Class 7 Maths Chapter 8 Comparing Quantities
NCERT Solutions For Class 7 Maths Chapter 9 Rational Numbers
NCERT Solutions For Class 7 Maths Chapter 10 Practical Geometry
NCERT Solutions For Class 7 Maths Chapter 11 Perimeter and Area
NCERT Solutions For Class 7 Maths Chapter 12 Algebraic Expressions
NCERT Solutions For Class 7 Maths Chapter 13 Exponents and Powers
NCERT Solutions For Class 7 Maths Chapter 14 Symmetry
NCERT Solutions For Class 7 Maths Chapter 15 Visualising Solid Shapes
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